Answer:
9.8×10^-4...... is the answer
The breakdown of NO3 in the day leads to more consumption of N2O5 in the day hence its concentration is greater at night than in the day.
<h3>What is equilibrium constant?</h3>
The equilibrium constant is a number that shows how much reactants are converted to products in a reaction. It is often shown as capital letter K in English.
Given the situation described in the question, we know that the concentration of N205 will be higher at night, because the decomposition of NO3(g) in the daytime will result in an increase in the rate of consumption of N2O5(g) to reform NO3(g).
Learn more about equilibrium constant: brainly.com/question/17960050
The answer is B.
<u>Each of the points or vertex represent a carbon atom. Answer choice B is the only choice that has 8. </u>
The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.
<h3>
Find the limiting reactant ?</h3>
- As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
- According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
- Therefore, only.083 mol of Sb4O6 are reacted.
- The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
- The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
- Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
- Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.
To learn more about limiting reactant refer to:
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Answer:
Freezing point solution = 70.131 °C
Explanation:
Step 1: Data given
Molality = 1.468 molal
A solution is created by dissolving biphenyl (C12H10) into naphthalene
Biphenyl is a non-electrolyte
Freezing point of naphthalene = 80.26 °C
Step 2: Calculate the freezing point depression
ΔT = i*Kf*m
⇒with ΔT = the freezing point depression = TO BE DETERMINED
⇒with i = the van't Hoff factor of biphenyl = 1
⇒with Kf = the freezing point depression constant of naphthalene = 6.90 °C/m
⇒with m = the molality = 1.468 molal
ΔT = 1 * 6.90 °C/m * 1.468 °C
ΔT = 10.13 °C
Step 3: Calculate the freezing point of the solution
ΔT = 10.13 °C
Freezing point solution = freezing point naphthalene - 10.13 °C
Freezing point solution = 80.26 °C - 10.129 °C
Freezing point solution = 70.131 °C
