Answer:
Here, we are required to determine the total energy of the reaction and determine if the reaction is an endothermic or exothermic reaction.
The correct answer is option C.
First, we need to determine the energy of the reaction.
The energy of the reaction is the change in enthalpy between the product and reactants.
Change of Enthalpy,
Hreaction = Hproduct - Hreactant.
Therefore, for the reaction above, the change in enthalpy is:
Hreaction = 590kJ/mol - 581kJ/mol.
Hreaction = 9kJ/mol.
Hence, since the reaction has an enthalpy change of 9kJ/mol, the reaction is endothermic (i.e energy is absorbed).
Explanation:
These ions are disjoint by the charge on the ion into four dissimilar tables and listed alphabetically within each table. Each polyatomic ion, has it called, chemical, formula, two dimensional drawing, and three dimensional representation are given.
The three dimensional buildings are drawn as CPK models. CPK structures represent the atoms as sphere, where the radius of the sphere is equal to the van der waals radius of the atom; these buildings give a measure up the volume of the polyatomic atom.
Aurous is a cation of gold. Gold takes the name "aurum" (Au) with atomic number of 79. In its purest form, the element is bright, slightly yellow, soft, ductile, and malleable. The charge of aurous is +1. Sulfide, on the other hand, has a charge of -2.
Hence, the chemical formula of the compound is Au₂S and its systematic name is gold (I) sulfide.
Answer:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)
Explanation:
Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:
- an equilibrium constant is, first of all, a fraction;
- in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
- in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
- each concentration should be raised to the power of the coefficient in the balanced chemical equation;
- only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.
Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)