In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be
5120 N - 4050 N = 1070 N
(it's positive, so the net vertical force is pointing upward)
In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be
950 N - 1520 N = -570 N
(negative means the net horizontal force points to the left)
So the net force on the balloon is the vector
<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>
(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)
The magnitude of the net force on the balloon is the magnitude of this vector:
<em>F</em> = √((1070 N)² + (-570 N)²)
<em>F</em> ≈ 1212 N
The light we see is red-shifted when we observe a galaxy that's moving AWAY FROM US.
Answer:
- It can put out more force than the input force by decreasing the distance through which force is applied.
- It can apply a force to an object in a different direction than the force applied to the machine.
Explanation:
Assuming the machine is a simple machine, such as a lever or pulley, the machine will not do any more work than is put into it. However, it can change the magnitude or direction (or both) of the input force required to achieve a particular output force.
Because the machine does not increase the work done, if the output force is greater, the output distance must be less.
The applicable observations are ...
- It can put out more force than the input force by decreasing the distance through which force is applied.
- It can apply a force to an object in a different direction than the force applied to the machine.
Answer:
distance and length are the same quantity
