Gases tend to deviate from the ideal gas law at
1 answer:
<h2>Answer: high pressures</h2>
The Ideal Gas equation is:
Where:
is the pressure of the gas
the number of moles of gas
is the gas constant
is the absolute temperature of the gas in Kelvin.
According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.
Now, real gases can behave approximately to an ideal gas, under the conditions described above.
However, when <u>temperature is low</u> these gases deviate from the ideal gas behavior, because the molecules move slowly, allowing the repulsion or attraction forces to take effect.
The same happens at <u>high pressures</u>, because the volume of molecules is no longer negligible.
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Answer:
4.15 m/s
Explanation:
As the total energy must be conserved (neglecting air resistance) the change in gravitational potential energy, must be equal to the change in kinetic energy:
ΔE = ΔK + ΔU =0
If we take as a zero reference level for the gravitational potential energy, the height of the swing seat above the ground, (which is equal to 0.21 m), we can find the initial gravitational energy, considering the height of the point where the seat is released, regarding this point:
h₀ = 1.09 m -0.21 m = 0.88 m
⇒ U₀ = m*g*h₀ = 400 N*0.88 m = 352 J
As Uf = 0, ΔU = Uf -U₀ = -352 J
As the swing starts from rest, K₀=0, so we can say:
ΔK = Kf = (1)
As ΔK = -ΔU ⇒ ΔK = 352 J (2)
From (1) and (2) we can solve for vf, as follows:
So, when the swing passes through its lowest position, Betty moves at 4.15 m/s.