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1 year ago

Iready math number line

Mathematics

1 answer:

natita [175]1 year ago

5 0

Answer:

the first equation or the one below it

Step-by-step explanation:

please mark me as brainliest

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Round seven point seven six to one decimal place

Rzqust [24]

7.76 to one decimal place

= 7.8

We are looking at one decimal place, in this case the number 7 after the decimal place next to 6. Any number above 5 rounds up the number in front of it. 6 is above 5 so it changes the 7 to an 8.

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2 years ago

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What is x - the square root of -2

Lena [83]

Sqrt(-2), can be written as i * sqrt(2). Thus, our answer is x - i sqrt(2).

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2 years ago

Ratio and Proportion problem<br>Please help meh

Anarel [89]

Answer:

hope its helpful to uh.......

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2 years ago

Part A: Use the computer output to determine the LSRL. Identify all the variables used in the equation. (3 points) Part B: What

gayaneshka [121]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

please find the correct question:

In choice a:

The smallest square line would be from the production.

$Sales = -7.567857143 + 0.917857143 \times Makeup\ Videos.$

Purchases of Cosmetics & Makeup Demo Clips are the factors used in the calculation.

In choice b:

The proportions of its variance of maquillage sales reveal by it's a linear relation to maquillage video tutorials is $99.53 \ \%$ .

In choice c:

Because the vector Cosmetics Demonstration videos are critical with 5.11E-07 p-value, which is less than 0.05 and $R^2 = 99.53$ . It may assume that increasing making-up purchases is attributed to tutorials for online makeup.

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2 years ago

Answer Question number 5 <br> Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$

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2 years ago