Answer:
Explanation:
Given parameters:
Volume of AgNO₃ = 1.3L
Molarity or concentration AgNO₃ = 0.245M
Unknown:
Mass of AgCl produced = ?
Solution:
To solve this problem, we have to work from the known compound to the unknown one using the mole concept.
The known compound is the one that we can obtain the value of the number of moles from. Here it is the given AgNO₃ that can furnish us with this piece of information;
Now let us establish the balanced reaction equation;
2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂
Now;
Find the number of moles of AgNO₃;
Number of moles of AgNO₃ = concentration x volume
= 1.3 x 0.245
= 0.32moles
From the balanced reaction equation;
2 mole of AgNO₃ produced 2 moles of AgCl
0.32 moles of AgNO₃ will produce 0.32moles of AgCl
Now that we know the number of moles of the AgCl, we can find the mass;
Mass of AgCl = number of moles x molar mass
Molar mass of AgCl = 107.9 + 35.5 = 143.4g/mol
Mass of AgCl = 0.32 x 143.4 = 45.89g
