Answer:
Density = 8.92 g/cm³
Explanation:
Density shows the relation of the mass and volume of a determined object. We have this deffinition:
Density = mass / volume
First of all, we calcualte the volume of the block of copper metal, with the data given:
8.4 cm . 5.5 cm . 4.6 cm = 212.52 cm³
Now we replace at the density formula:
Density = 1896 g /212.52 cm³ = 8.92 g/cm³
The right answer is C.
Oxidation is the loss of electrons. A loss of electrons will appear as an increase in the positive charge of the element as it is converted to an ion. Here we have aluminum have an oxidation state equals zero as a reactant because it is in the element state. After reacting, it combines with three atoms chlorine where each chlorine atom usually has an oxidation state equals -1, therefore, we have -3 charges which have to be neutralized with the 3+ charges of aluminum.
Answer:
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
Explanation:
First of all, we out down the skeleton equation;
Al + MnO4- → MnO2 + Al(OH)4-
Secondly, we write the oxidation and reduction equation in basic medium;
Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-
Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-
Thirdly, we add the two half reactions together to obtain:
Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-
Lastly, cancel out species that occur on both sides of the reaction equation;
Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O
The simplified equation now becomes;
Al + MnO4- + 2H2O → Al(OH)4- + MnO2
When cohesive force is stronger than the adhesive force: concave up meniscus, water forms droplets on surface
Water solubility of oxygen at 25oC and pressure = 1 bar is at 40 mg/L water. In air with a normal composition the oxygen partial pressure is 0.2 atm. This results in dissolution of 40 . 0.2 = 8 mg O2/L in water that comes in contact with air.
