<span>Cost and availability of fuel is a considerable factor when dealing with nuclear power. Fission requires an element that can be easily split in a particle accelerator, such as uranium or plutonium. Fusion, on the other hand, uses isotopes of hydrogen atoms, specifically deuterium and tritium, that can be obtained from ordinary water</span>
        
             
        
        
        
Given that the volume and amount  of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C
        
             
        
        
        
Answer:
The temperature to the nearest 0.5°C is 98.5°C
 
        
             
        
        
        
Answer:
1.36 × 10³ mL of water.
Explanation:
We can utilize the dilution equation. Recall that: 

Where <em>M</em> represents molarity and <em>V</em> represents volume. 
Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁: 

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus: 

Convert this value to mL: 

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution. 
 
        
             
        
        
        
Answer:
the volume delivered by the pipette = 22.32 mL
Explanation:
To calculate this, let us first note that the density of water relates it weight and its volume (density = mass ÷ volume), hence we are going to use density to determine the volume.
Density of water = mass/volume = 0.997 g/ mL
mass = 22.25g
Density = 0.997g/mL
volume = ?

∴ the volume delivered by the pipette = 22.32 mL
<em>Please note that this calculation is based on the fact that the weight of the empty flask has been determined and canceled out.</em>