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kolbaska11 [484]
3 years ago
14

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 42.9 kPa. What is the partial pressure of

carbon dioxide if the partial pressure of oxygen is 6.6 kPa and the partial pressure of nitrogen is 23.0 kPa?
Chemistry
2 answers:
Lady bird [3.3K]3 years ago
4 0
The total Pressure equals the sum of all pressures contained 

<span>Since total pressure and the pressure of nitrogen and oxygen is given, finding the pressure of carbon dioxide is given by: </span>

<span>Pressure of Carbon dioxide = 42.9- 6.6- 23.0 </span>
<span>=13.3kPa </span>
timofeeve [1]3 years ago
4 0

Answer : The partial pressure of the carbon dioxide gas is, 13.3 kPa

Solution :

According to the Dalton's law of partial pressures, the total pressure of an ideal gas mixture is equal to the sum of the partial pressures of the gases in the mixture.

P_T=P_{O_2}+P_{N_2}+P_{CO_2}

where,

P_T = total pressure = 42.9 kPa

P_{O_2} = partial pressure of oxygen gas = 6.6 kPa

P_{N_2} = partial pressure of nitrogen gas = 23.0 kPa

P_{CO_2} = partial pressure of carbon dioxide gas = ?

Now put all the given values in the above formula, we get the partial pressure of carbon dioxide gas.

42.9=6.6+23.0+P_{CO_2}

P_{CO_2}=13.3kPa

Therefore, the partial pressure of the carbon dioxide gas is, 13.3 kPa

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Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in
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Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is  2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

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\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\   \frac{m_{S} }{m_{O} }= 2

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For SO₂,

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If I have 17 liters of gas at 67C and 88.89 atm, what will be the pressure of the gas if I raise the temperature to 94C and decr
dmitriy555 [2]

Answer:

The correct answer is A. 140 atm

Explanation:

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3 years ago
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