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kolbaska11 [484]
3 years ago
14

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 42.9 kPa. What is the partial pressure of

carbon dioxide if the partial pressure of oxygen is 6.6 kPa and the partial pressure of nitrogen is 23.0 kPa?
Chemistry
2 answers:
Lady bird [3.3K]3 years ago
4 0
The total Pressure equals the sum of all pressures contained 

<span>Since total pressure and the pressure of nitrogen and oxygen is given, finding the pressure of carbon dioxide is given by: </span>

<span>Pressure of Carbon dioxide = 42.9- 6.6- 23.0 </span>
<span>=13.3kPa </span>
timofeeve [1]3 years ago
4 0

Answer : The partial pressure of the carbon dioxide gas is, 13.3 kPa

Solution :

According to the Dalton's law of partial pressures, the total pressure of an ideal gas mixture is equal to the sum of the partial pressures of the gases in the mixture.

P_T=P_{O_2}+P_{N_2}+P_{CO_2}

where,

P_T = total pressure = 42.9 kPa

P_{O_2} = partial pressure of oxygen gas = 6.6 kPa

P_{N_2} = partial pressure of nitrogen gas = 23.0 kPa

P_{CO_2} = partial pressure of carbon dioxide gas = ?

Now put all the given values in the above formula, we get the partial pressure of carbon dioxide gas.

42.9=6.6+23.0+P_{CO_2}

P_{CO_2}=13.3kPa

Therefore, the partial pressure of the carbon dioxide gas is, 13.3 kPa

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<h3>Answer:</h3>

Theoretical mass = 17.42 g

Percent yield of Fe = 86.11%

<h3>Explanation:</h3>

The equation for the reaction between iron (iii) oxide and carbon monoxide is given by;

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

We are required to calculate the theoretical yield and the percentage yield of Iron.

Step 1: Moles of iron (iii) oxide

Moles are given by dividing the mass of the compound by the molar mass.

Molar mass of Iron(iii) oxide = 159.69 g/mol

Moles of Iron(III) oxide = 25 g ÷ 159.69 g/mol

                                     = 0.156 moles

Step 2: Moles of Iron produced

From the equation 1 mole of Iron(iii) oxide reacts to produce 2 moles of Fe.

Therefore, the mole ratio of Fe₂O₃ to Fe is 1 : 2.

Thus, moles of Fe = Moles of Fe₂O₃ × 2

                              = 0.156 moles × 2

                              = 0.312 moles

Step 3: Theoretical mass of iron produced

To calculate the mass of iron we multiply the number of moles of iron with the relative atomic mass.

Relative atomic mass = 55.845

Mass of iron = 0.312 moles × 55.845

                    = 17.42 g

Step 4: Percent yield of iron

% yield = (Actual mass ÷ Theoretical mass)×100

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A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.
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Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

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When an ideal gas goes from a state 1 to a state 2, it is true:

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Replacing:

\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}

Solving:

T2=350 kPa*\frac{291 K}{180 kPa}

T2= 565.83 K

<u><em>The new temperature will be 565.83 K.</em></u>

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