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marta [7]
2 years ago
9

Ben thinks that the largest place value that 5.6 and 1.78 have in common is the tenths place. Nichole thinks that the largest pl

ace value they have in common is the ones place.
Answer the following in complete sentences:

Who is correct, Ben or Nichole?
Write how you would explain your answer to the person who answered incorrectly.
Mathematics
1 answer:
-Dominant- [34]2 years ago
3 0

The place values in 5.6 and 1.78 are the positions of the digits in the numbers

  • The largest place value common in 5.6 and 1.78 is the ones place
  • Nichole is correct

<h3>How to determine who is correct?</h3>

In a number, the non-zero digit at the left-most position is the greatest place value

This means that:

The greatest place value in 5.6 is 5 (i.e. ones place)

The greatest place value in 1.78 is 1 (i.e. ones place)

So, we can conclude that the largest place value common in 5.6 and 1.78 is the ones place

Hence, Nichole is correct

Read more about place values at:

brainly.com/question/12386995

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The x coordinate of the solution to the system of equations y=x+4 and 3y=-2x+2
Vera_Pavlovna [14]
<h2>Hello!</h2>

The answer is:

The x-coordinate of the solution to the system of equations is:

x=-2

<h2>Why?</h2>

We can solve the problem writing both equations as a system of equations.

So, we are given the equations:

\left \{ {{y=x+4} \atop {3y=-2x+2}} \right.

Then, solving by reduction we have:

Multiplying the first equation by 2 in order to reduce the variable "x", we have:

\left \{ {{2y=2x+2*4} \atop {3y=-2x+2}} \right.

5y=2x-2x+8+2\\\\5y=8+2\\\\y=\frac{10}{5}=2

Now, substituting "y" into the first equation, to isolate "x" we have:

y=x+4\\\\2=x+4\\\\x=2-4=-2

Hence we have that the x-coordinate of the solution to the system of equations is

x=-2

Have a nice day!

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3 years ago
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A tile is selected from seven tiles, each labeled with a different letter from the first seven letters of the alphabet.
MArishka [77]

Answer:

Step-by-step explanation:

U= {A,B,C,D,E,F,G}

X = {A, B, C, D}

Y = {A, C, E, F}

a) X or Y = {A, B, C, D} and {A, C, E, F} = {A, B, C, D, E, F}

B) X and Y = {A, B, C, D} or {A, C, E, F} = {A, C}

c) Complement of X = {A,B,C,D,E,F,G} - {A, B, C, D} = {B,D,G}

7 0
3 years ago
How many points do you need to be able to private message someone?
densk [106]

Answer:

1000 points and need to be moderator

Step-by-step explanation:

1000 points to open messages and need to be moderator or above to send messages

6 0
3 years ago
Identify the outliers of the data set. Then determine if the outlier increases or decreases the value of the mean.
Juli2301 [7.4K]
<h3>Answer:  D) 76; increases</h3>

========================================================

Explanation:

The main group or cluster of values spans from 32 to 42 (inclusive).

Then off on its own is the value 76, which we consider an outlier. This value is fairly far from the group. As a rule, large outliers pull on the arithmetic mean to make it larger than it should be. Think of it like the outlier pulling on the mean as if it was done through a magnet or gravitational pull.

Similarly, small outliers pull the mean to the left to make it smaller than it should be. We don't have any small outliers in this case.

--------------

Let's consider the set

A = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 46}

where I've sorted the values and I replaced 76 with 46.

Computing the mean of set A gets us

(32+34+35+36+37+38+38+41+42+42+46)/11 = 38.27 approximately

--------------

Now let's form this set

B = {32, 34, 35, 36, 37, 38, 38, 41, 42, 42, 76}

which is the original set your teacher gave you. It's nearly identical to set A, except that the 46 is now 76 again.

Compute the mean of set B

(32+34+35+36+37+38+38+41+42+42+76)/11 = 41

---------------

Set A has a mean of roughly 38.72 and set B has a mean of 41. We see that the mean has increased.

3 0
3 years ago
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