The different in size of each of the rope's pullers, correspond to a difference in the magnitude of the applied force, such that
1 answer:
Answer:
F = - 50 N
Hence, the magnitude of resultant force is 50 N and its direction is leftwards.
Explanation:
The magnitude of the resultant force is always equal to the sum of all forces. While, the direction of resultant force will be equal to the direction of the force with greater magnitude:
considering right direction to be positive:
F₁ = Force applied on right rope = 150 N
F₂ = Force applied on left rope = 200 N
Therefore, the resultant force can be found by using these values in equation:
<u>F = - 50 N</u>
<u>Hence, the magnitude of resultant force is 50 N and its direction is leftwards.</u>
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Explanation:
I just answer the second question
To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.
The work done would be defined as
Where,
PE = Potential Energy
KE = Kinetic Energy
Where,
m = Mass
g = Gravitational energy
h = Height
v = Velocity
Considering power as the change of energy as a function of time we will then have to
The rate of mass flow is,
Where,
= Density of water
A = Area of the hose
The given radius is 0.83cm or m, so the Area would be
We have then that,
Final the power of the pump would be,
Therefore the power of the pump is 57.11W