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sashaice [31]
3 years ago
7

The different in size of each of the rope's pullers, correspond to a difference in the magnitude of the applied force, such that

: le 150N 100N SON SON 4. Apply a 200N force to the left rope, and 150 N to the right rope. What is the magnitude and direction of the Resultant Force?
Physics
1 answer:
olga55 [171]3 years ago
5 0

Answer:

F = - 50 N

Hence, the magnitude of resultant force is 50 N and its direction is leftwards.

Explanation:

The magnitude of the resultant force is always equal to the sum of all forces. While, the direction of resultant force will be equal to the direction of the force with greater magnitude:

Resultant\ Force = F = F_{1} - F_{2}

considering right direction to be positive:

F₁ = Force applied on right rope = 150 N

F₂ = Force applied on left rope = 200 N

Therefore, the resultant force can be found by using these values in equation:

F = 150\ N - 200\ N

<u>F = - 50 N</u>

<u>Hence, the magnitude of resultant force is 50 N and its direction is leftwards.</u>

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Read 2 more answers
A ray of light passes symmetrically through on equilateral prism of refractive index 1.5. determine
Darina [25.2K]

Answer:

Angle  \: at  \: which \:  minimum \: deviation \:  occur = 37.18\degree

Explanation:

<em>Given:</em>

Refractive index of prism μ = 1.5

Since the prism is equilateral,

Angle of prism A= 60°

<em>To find:</em>

Angel of incidence for which minimum deviation can occur(δm) ?

<em>Solution:</em>

We know that,

The refractive index, Angle of prism and angle of minimum deviation are correlated with formula,

<em>\mu \:  =  \frac{sin( \frac{A + \delta_m}{2} )}{sin \frac{A}{2} }</em>

Where symbols have their usual meaning.

Substituting the value from given data in formula,

<em>\mu \:  =  \frac{sin( \frac{A + \delta_m}{2} )}{sin \frac{A}{2} }  \\1.5\:  =  \frac{sin( \frac{60 + \delta_m}{2} )}{sin \frac{60}{2} }  \\  {sin( \frac{60 + \delta_m}{2} )} = 1.5 \times sin30 \\ {sin( \frac{60 + \delta_m}{2} )} = 1.5 \times 0.5 \\ {sin( \frac{60 + \delta_m}{2} )} = 0.75 \\ \frac{60 + \delta_m}{2} =  {sin}^{ - 1}(0.75) \\ \frac{60 + \delta_m}{2} = 48.59 \: \degree \\ \delta_m = (48.59 \times 2) - 60\degree \\ \delta_m = (48.59 \times 2) - 60\degree \\ \delta_m = (97.18 - 60)\degree \\  \delta_m = 37.18\degree</em>

<em>Angle  \: at  \: which \:  minimum \: deviation \:  occur = 37.18\degree</em>

<u><em>Thanks </em><em>for </em><em>joining </em><em>brainly </em><em>community</em><em>!</em></u>

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2 years ago
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