1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lilavasa [31]
3 years ago
8

Steve want to catch up to Cami, a girl he likes. If he is jogging at 8 m/s and she is walking at 1 m/s. How long will it take hi

m to reach her if they are 10 meters apart?
Physics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>

<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>

Explanation:

Distance between them is 10 m

Speed  ( if they are moving towards each other)= distance/time

time = 10/8+1

time = distance / speed= 10/9=  1.11 secs

if they are moving away from each other than it will take

time = 10/8-1= 10/7= 1.43 secs

You might be interested in
HELP PLEASE
denis-greek [22]
B) Distance: the farther, the weaker!
4 0
4 years ago
Read 2 more answers
In projectile mtion, what is the y-component of the initial velocity? if V= Vi = 100 m/s and the angle with horizontal axis Θ =
Damm [24]

Answer:

hence the y - component of the velocity is 50m/s

4 0
3 years ago
At a temperature of 250 K, the gas in a cylinder has a volume of 20 L. If the temperature increased to 260 K, what must the volu
masya89 [10]

Answer:b.20.8L

Explanation:

Since pressure is constant we can use the equation V1/T1 = V2/T2

(20/250)=(x/260)

5200=250x

X=20.8

3 0
4 years ago
A 12.0 kg block rests on an inclined plane. The plane makes an angle of 31.0° with the horizontal, and the coefficient of fricti
allochka39001 [22]

Answer:

The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

Explanation:

Given that,

Mass = 12.0 kg

Angle = 31.0°

Friction coefficient = 0.158

Mass of second block = 38.0 kg

Using formula of frictional force

f_{\mu} = \mu N....(I)

Where, N = normal force

N = mg\cos\theta

Put the value of N into the formula

N =12\times9.8\times\cos 31^{\circ}

N=100.80\ N

Put the value of N in equation (I)

f_{mu}=0.158\times100.80

f_{mu}=15.9264\ N

Now, Weight of second block

W = mg

W=38.0\times9.8

W=372.4\ N

The horizontal force is

F = mg\sintheta

F=12\times9.8\times\sin 31^{\circ}

F=60.5684\ N....(II)

(I). We need to calculate the acceleration

a=m_{2}g-\dfrac{f_{\mu}+mg\sin\theta}{m_{1}+m_{2}}

a=\dfrac{372.4-(15.9264+60.5684)}{12+38}

a=5.92\ m/s^2

(II). We need to calculate the tension in the rope

m_{2}g-T=m_{2}a

-T=38\times5.92-38\times9.8

T=147.44\ N

Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

5 0
4 years ago
A cat accelerates from rest to 10m/s when it sees a dog. This takes 2 seconds. What was the acceleration of the cat
Nookie1986 [14]
The formula is a= chance in velocity/time
A=10-0/2
A=10/2
A=5 m/s^2 (meters per second squared)
5 0
3 years ago
Read 2 more answers
Other questions:
  • On a production possibilities curve, any point that falls outside the frontier line is considered
    5·1 answer
  • GUYS I NEEEED THIS SOON. HELLLPPPP!!!
    13·1 answer
  • Which body system processes into a useable source of energy
    10·1 answer
  • True or false friction makes energy vanish
    13·2 answers
  • A(n) ______ particle consists of two protons and neutrons.
    9·2 answers
  • two cubes are made of silver and have equal edges. one of the cubes i hollow. explain how to determine the volume of the space i
    13·1 answer
  • Describe the path of the electric current through a circuit?​
    10·1 answer
  • What is the electric potential of a 4.5 × 10-5 C charge that has an electric potential energy of 0.027 J?
    7·2 answers
  • Someone pls help me with this!
    7·1 answer
  • What is the BMI if the Hight=165 and Wight= 80<br> Options :<br> •20<br> •17<br> •22<br> •0 29.4
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!