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lilavasa [31]
3 years ago
8

Steve want to catch up to Cami, a girl he likes. If he is jogging at 8 m/s and she is walking at 1 m/s. How long will it take hi

m to reach her if they are 10 meters apart?
Physics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>

<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>

Explanation:

Distance between them is 10 m

Speed  ( if they are moving towards each other)= distance/time

time = 10/8+1

time = distance / speed= 10/9=  1.11 secs

if they are moving away from each other than it will take

time = 10/8-1= 10/7= 1.43 secs

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Classify the statements as correct or incorrect.
alexandr402 [8]

Explanation:

  • A thermometer does measure the temperature of a body and not the heat. It is known that temperature is a measure of average kinetic energy.

Therefore, the statement a thermometer measures  the average kinetic energy  of a substance is correct.

  • Heat is a form of energy as it can make a colder substance become hot and it moves from one place to another. Thus, the statement heat is a form of energy is correct.
  • Also, heat flows from hotter substance to colder substance. Hence, the statement heat flows from a colder  substance to a hotter  substance is correct.
  • Convection is a property of fluids or gases which makes less denser (hot) material to rise and more denser (colder) material to sink.

Therefore, the statement convection occurs only  in liquids and gases is correct.

  • All substances radiate heat is an incorrect statement. For example, a thermos bottle does not radiate heat.
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6 0
4 years ago
Read 2 more answers
As a result of friction, the angular speed of a wheel changes with time according to dθ/dt = ω0e^−σt where ω0 and σ are constant
NNADVOKAT [17]

Hi there!

a.

We can use the initial conditions to solve for w₀.

It is given that:

\frac{d\theta}{dt} = w_0e^{-\sigma t}

We are given that at t = 0, ω =  3.7 rad/sec. We can plug this into the equation:

\omega(0)= \omega_0e^{-\sigma (0)}\\\\3.7 = \omega_0 (1)\\\\\omega_0 = \boxed{3.7 rad/sec}

Now, we can solve for sigma using the other given condition:

2 = 3.7e^{-\sigma (8.6)}\\\\.541 = e^{-\sigma (8.6)}\\\\ln(.541) = -\sigma (8.6)\\\\\sigma = \frac{ln(.541)}{-8.6} = \boxed{0.0714s^{-1}}

b.

The angular acceleration is the DERIVATIVE of the angular velocity function, so:

\alpha(t) = \frac{d\omega}{dt} = -\sigma\omega_0e^{-\sigma t}\\\\\alpha(t) = -(0.0714)(3.7)e^{-(0.0714) (3)}\\\\\alpha(t) = \boxed{-0.213 rad\sec^2}

c.

The angular displacement is the INTEGRAL of the angular velocity function.

\theta (t) = \int\limits^{t_2}_{t_1} {\omega(t)} \, dt\\\\\theta(t) = \int\limits^{2.5}_{0} {\omega_0e^{-\sigma t}dt\\\\

\theta(t) = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=2.5} \atop {t_1=0}} \right.

\theta = -\frac{3.7}{0.0714}e^{-0.0714 t}\left \| {{t_2=2.5} \atop {t_1=0}} \right. \\\\\theta= -\frac{3.7}{0.0714}e^{-0.0714 (2.5)} + \frac{3.7}{0.0714}e^{-0.0714 (0)}

\theta = 8.471 rad

Convert this to rev:

8.471 rad * \frac{1 rev}{2\pi rad} = \boxed{1.348 rev}

d.

We can begin by solving for the time necessary for the angular speed to reach 0 rad/sec.

0 = 3.7e^{-0.0714t}\\\\t = \infty

Evaluate the improper integral:

\theta = \int\limits^{\infty}_{0} {\omega_0e^{-\sigma t}dt\\\\

\lim_{a \to \infty} \theta = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=a} \atop {t_1=0}} \right.

\lim_{a \to \infty} \theta = -\frac{3.7}{0.0714}e^{-0.0714a} + \frac{3.7}{0.0714}e^{-0.0714(0)}\\\\ \lim_{a \to \infty} \theta = \frac{3.7}{0.0714}(1) = 51.82 rad

Convert to rev:

51.82 rad * \frac{1rev}{2\pi rad} = \boxed{8.25 rev}

8 0
3 years ago
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
dedylja [7]
I’m almost 100 percent sure it’s the first one
4 0
3 years ago
A copper wire 225m long must experience a voltage drop of less than 2.0v when a current of 3.5 a passes through it. compute the
MA_775_DIABLO [31]

Answer:

V = I * R

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R = ρ L / A  where R is proportional to L and inversely proportional to A

A = ρ L / R     minimum area of wire

ρ = 1 / μ  =     1.67E-8 ohm-m      resistivity inverse of conductivity

A = 1.67E-8 ohm-m * 225 m / .571 ohm = 6.68E-6 m^2

A = 6.68 mm^2       since 1 mm^2 = 10-6 m^2   or 1 mm = 10-3 m

A = Π r^2 = 6.68 mm^2

r = (6.68 / 3.14)^1/2 mm = 2.13 mm      radius of wire

d = 2 * r = 4.26 mm

5 0
2 years ago
Using the rules for significant figures, what do you get when you multiply 67.6 by 1.2?
Paul [167]

Answer:

B. 81

Explanation:

When you multiply two numbers, round the answer to the least number of significant figures available.  67.6 has three significant figures, and 1.2 has two significant figures.  So we round to two significant figures.

3 0
3 years ago
Read 2 more answers
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