They give us the cable tension t = 1500 newton. We assume that the mass of the cable is negligible compared to that of the tower.
We have a force t of 1500 Newton. This force has a vertical component on the y axis and a horizontal component on the x axis.
Of these two components of force, we are especially interested in calculating is the magnitude of the vertical component.
If the angle that it forms with the ground is 50 °, then the vertical component of the force is:
Fy = 1500sin (50)
Fy = 1149 N. <1200 N
The wire will not be loose
Explanation:
It is given that,
Speed of the baseball, u = 44 m/s
Speed of the baseball, v = 53 m/s
Mass of the ball, m = 145 g = 0.145 kg
Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s
F₁ = 2900 N...........(1)
F₂ = 3493.18 N.........(2)
In average vector form force is given by :
Hence, this is the required solution.
Answer:
1. Dry Beans - 591.75 kg/m^3
2. Flour - 593 kg/m^3
3. Wax - 900 kg/m^3
4. Wet sand - 2039 kg/m^3
5. Chalk - 2499 kg/m^3
6. Talcum Powder - 2776 kg/m^3
7. Copper - 8960 kg/m^3
Explanation:
Make sure your units are the same
<span>On the scale the only external forces are the man's weight acting downwards and the normal force which the scale exerts back to support his weight.
So F = Ma = mg + Fs
The normal force Fs (which is actually the reading on the scale) = Ma + Mg
But a = 0
So Fs = Mg which is just his weight.
Fs = 75 * 9.8 = 735N</span>
Answer:
If F is a constant, we can take f = 1
f = m×a
ma = 1
therefore we can say that force is hence proportinal to the product of mass and acceleration.
