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VMariaS [17]
3 years ago
7

A 17-car train standing on the siding is started in motion by the train’s engine. 9 cm slack is between each of the cars, which

are 9 m long. The engine is tightly connected to the first car and moves at a constant speed of 36 cm/s. How much time is required for the pulse to travel the length of the train? Answer in units of s.
Physics
1 answer:
BaLLatris [955]3 years ago
6 0

Answer:

4 seconds

Explanation:

There are links between cars, they are in between

1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9, 9-10, 10-11, 11-12, 12-13, 13-14, 14-15, 15-16, 16-17.

Here 1 represents the first car which is firmly attached to the engine. So, there are 16 links and each link has a slack of 9 m.

So, total slack

9×16 = 144 cm

Speed of train = 36 cm/s

\text{Time taken by the pulse}=\frac{Length}{speed}\\\Rightarrow \text{Time taken by the pulse}=\frac{144}{36}\\\Rightarrow \text{Time taken by the pulse}=4\ s

Time taken by the pulse to travel the length of train is 4 seconds.

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Dante is leading a parade across the main street in front of city hall. Starting at city hall, he marches the parade 4 blocks ea
Ipatiy [6.2K]

Answer:

The correct option is A)

Displacement: 6.71 m, Direction: 63.4 degrees north of east

Explanation:

Given that Dante is leading a parade across the main street in front of city hall.

Let, Initial location of parade is 0i+0j

One block of city is one units on the XY- graph

Statement 1: Parade marches the parade 4 blocks east, then 3 blocks south

New location of parade is 4i-3j

Statement 2: The parade marches 1 block west and 9 blocks north and finally stops.

Final location of parade is (4i-3j)+(-1i+9j)=3i+6j

Displacement is given by

Displacement = (Final destination)-(Initial destination)

Displacement = (3i+6j)-(0i+0j)=3i+6j

Thus,

Magnitude of displacement = \sqrt{3^{2}+6^{2}}

                                              = 6.71 m

Direction of displacement =  tan^{-1}(\frac{Y}{X} )

                                           =  tan^{-1}(\frac{6}{3} )

                                           = 63.43 NE

Therefore, the correct option is A) Displacement: 6.71 m, Direction: 63.4 degrees north of east

5 0
3 years ago
Magnesium is a highly flammable element which is easily combustible in the presence of oxygen:
NemiM [27]

4 atoms

Explanation:

On the product side, we expect to find 4 atoms of the product.

    An atom is the smallest indivisible particle that takes part in a chemical reaction.

    An element is a distinct substance that cannot be split-up into simpler substances. Such substances consist of only one kind of atom.

    In this reaction we have:

       2 elements:             Mg                O

on the reactant side:

   We have two moles of Mg:   2 atoms of Mg

            1 mole of oxygen gas:   2 atoms of O

                             total atoms:    4 atoms

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".

We expect to find 4 atoms of products which is MgO on the product side.

              2Mg + O₂ →  2MgO + heat

Learn more:

Conservation of matter brainly.com/question/2190120

#learnwithBrainly

     

   

       

3 0
3 years ago
Read 2 more answers
A consequence of more mass having more inertia is that _____ is required to bring the helicopter to the same speed as the bullet
____ [38]

Answer:

<em>The answer to your question is </em><em>more force</em>

Explanation:

<em>A consequence of more mass having more inertia is that more force is required to bring the helicopter to the same speed as the bullet </em>

<u><em>I hope this helps and have a good day!</em></u>

7 0
2 years ago
Place the following types of electromagnetic radiation in order of increasing wavelength. ultraviolet light gamma rays radio wav
kvv77 [185]

Answer: gamma rays < ultraviolet light < radio waves

Explanation: We have to explain the ordering we take into account a relationship for electromagnetic wave, which is given by:

c=λ*ν c is the speed of light.  λ and ν are the wavelegth and the frequency of the waves.

Then we also know that the high frequency of these radiation correspond to the gamma ray (10^18 1/s) while the lowest correspond to radio wave (10^8 1/s) so:

The ultraviolet ligth is ranged at frequencies of 10^16 1/s located bewteen gamma and radio radiation.

as large frequency lower wavelength we can order these radiations from short to long wavelengths as follows:

gamma rays < ultraviolet light < radio waves

3 0
3 years ago
How much work must be done by frictional forces in slowing a 1000-kg car from 26.1 m/s to rest? a.3.41 x 10^5 J b.2.73 x 10^5 J
algol13

Answer:

Work done by the frictional force is 3.41\times 10^5\ J

Explanation:

It is given that,

Mass of the car, m = 1000 kg

Initial velocity of car, u = 26.1 m/s

Finally, it comes to rest, v = 0

We have to find the work done by the frictional forces. Work done is equal to the change in kinetic energy as per work - energy theorem i.e.

W=k_f-k_i

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 1000\ kg(0^2-(26.1\ m/s)^2)

W = −340605 J

or

W=3.41\times 10^5\ J

Hence, the correct option is (a).

6 0
3 years ago
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