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VMariaS [17]
3 years ago
7

A 17-car train standing on the siding is started in motion by the train’s engine. 9 cm slack is between each of the cars, which

are 9 m long. The engine is tightly connected to the first car and moves at a constant speed of 36 cm/s. How much time is required for the pulse to travel the length of the train? Answer in units of s.
Physics
1 answer:
BaLLatris [955]3 years ago
6 0

Answer:

4 seconds

Explanation:

There are links between cars, they are in between

1-2, 2-3, 3-4, 4-5, 5-6, 6-7, 7-8, 8-9, 9-10, 10-11, 11-12, 12-13, 13-14, 14-15, 15-16, 16-17.

Here 1 represents the first car which is firmly attached to the engine. So, there are 16 links and each link has a slack of 9 m.

So, total slack

9×16 = 144 cm

Speed of train = 36 cm/s

\text{Time taken by the pulse}=\frac{Length}{speed}\\\Rightarrow \text{Time taken by the pulse}=\frac{144}{36}\\\Rightarrow \text{Time taken by the pulse}=4\ s

Time taken by the pulse to travel the length of train is 4 seconds.

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Answer:

Secondary voltage of transformer is 905.23 volt  

Explanation:

It is given number of turns in primary of transformer N_1=275

Number of turns in secondary N_2=2200

Input voltage equation of the transformer

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Here v_{max}=160volt

v_{rms}=\frac{160}{\sqrt{2}}=113.15volt

For transformer we know that

\frac{V_1}{V_2}=\frac{N_1}{N_2}

\frac{113.15}{V_2}=\frac{275}{2200}

V_2=905.23Volt

Therefore secondary voltage of transformer is 905.23 volt

6 0
3 years ago
A plate glass window (n = 1.5 has a thickness of 3.6 mm. how long does it take light to pass perpendicularly through the plate?
Artyom0805 [142]
Hope this helps you.

8 0
3 years ago
At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into osci
aksik [14]

Answer:

Explanation:

Answer:

4.53 kg

Explanation:

spring constant, K = 16 N/m

Amplitude, A = 20 cm = 0.2 m

Maximum speed, v = 37.6 cm/s = 0.376 m/s

The formula for maximum speed is given by

v = ωA

where, ω is the angular frequency

0.376 = ω x 0.2

ω = 1.88 rad/s

\omega =\sqrt{\frac{K}{m}}

m = \frac{K}{\omega ^{2}}

m = \frac{16}{1.88 ^{2}}

m = 4.53 kg

Thus, the mass of banana bunch is 4.53 kg.

8 0
3 years ago
A 71-kg swimmer dives horizontally off a 500-kg raft. If the diver's speed immediately after leaving the raft is 6m/s, what is t
Sloan [31]

Answer:

The answer is below

Explanation:

Momentum is used to measure the quantity of motion in an object. Momentum is the product of mass and velocity.

Momentum = mass * velocity

The principle of conservation of momentum states that momentum cannot be created or destroyed but  can be transferred. Therefore the momentum before and after an action is equal.

Initial momentum = Final momentum

Let m be the mass of the diver, M be the mass of the raft, u be the initial velocity of the diver, U be the initial velocity of the raft, v be the final velocity of the diver and V be the final velocity of the raft.

m = 71 kg, M = 500 kg, v = 6 m/s

Initial both the raft and diver are at rest, hence u and U is zero, hence:

mu + MU = mv + MV

71(0) + 500(0) = 71(6) + 500(V)

0 = 426 + 500(V)

500(V) = -426

V = -426/500

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5 0
3 years ago
Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.7 m tall window in 0.129 sec. From how high above th
vladimir1956 [14]

Answer:

h = 22.35 m

Explanation:

given,

initial speed of the rock,u = 0 m/s

length of the window,l = 2.7 m

time taken to cross the window,t = 0.129 s

Speed of the rock when it crosses the window

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v = \dfrac{2.7}{0.129}

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height of the building above the window

using equation of motion

v² = u² + 2 g h

20.93² = 0² + 2 x 9.8 x h

h = 22.35 m

Hence, the height of the building above the top of window is equal to h = 22.35 m

8 0
2 years ago
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