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astra-53 [7]
3 years ago
13

Someone please help. science <3 thx ill give 15 pts for it.

Physics
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

put these numbers in the boxes from up to down. hope this helps! :)

Explanation:

7

6

3

1

8

4

2

5

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16. An object has a mass of 13.5 kilograms. What force is required to accelerate it to a rate of 9.5 m/s2?
V125BC [204]
D. 128.25 because force=mass x acceleration
8 0
4 years ago
Read 2 more answers
A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and
iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g

The speed at this point would then be

v^2 = a_c r = 2gr = 2*9.8*17 = 333.2

v = \sqrt{333.2} = 18.25 m/s

2. Similarly, if T = mg, then the centripetal acceleration must be

a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0
4 years ago
What has a greatest (most substantial/ most influential) effect on the strength of the force of
xxTIMURxx [149]

Answer:

The force of gravity effected by stream the was muscle in the earth.

Explanation:

It just was

4 0
3 years ago
Object A is negatively Charged. object A and Object B attract. Object B and Object C repel. Object C and Object D attract. What
3241004551 [841]

Remember opposites attract and same charges repel each other.

Object A= negatively charged.

Object A and B attract so B must be positively charged.

Object B and C repel so because B is positively charged C must also be positively charged.

Object C and D attract and because C is positively charged, D must be negatively charged.

5 0
4 years ago
Consider a plywood square mounted on an axis that is perpendicular to the plane of the square and passes through the center of t
belka [17]

Answer:

T= 8.061N*m

Explanation:

The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:

T = Fr

where F is the force, r the radius.

if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.

Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:

r = \sqrt{(0.38m)^2+(0.38m)^2}

r = 0.5374m

Finally, replacing the value of r and F, we get that the maximun torque is:

T = 15N(0.5374m)

T= 8.061N*m

4 0
4 years ago
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