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viva [34]
3 years ago
6

A stream of warm air with a dry-bulb temperature of 36°C and a wet-bulb temperature of 30°C is mixed adiabatically with a stream

of saturated cool air at 12°C. The dry air mass flow rates of the warm and cool airstreams are 8 and 10 kg/s, respectively. Assuming a total pressure of 1 atm, determine (a) the temperature, (b) the specific humidity, and (c) the relative humidity of the mixture.
Physics
1 answer:
rewona [7]3 years ago
6 0

Answer:

Explanation:

  Given

T_1\left ( DBT\right )=36^{\circ}C

WBT=30^{\circ}C

m_1=8 kg/s

m_2=10 kg/s

Now total mass m_3=sum of m_1+m_2

m_3=8+10=18 kg/sec

Now from Steam table at DBT=36^{\circ}C & WBT=30^{\circ}C

\omega _1=0.025kg\kg of dry air

for saturated cool air at 12^{\circ}C

Humidity ratio \omega _2=0.0085 kg\kg of dry air

Now

m_1\omega _1+m_2\omega _2=m_3\omega _3

8\cdot 0.025+10\cdot 0.0085=18\cdot \omega _3

\omega _3=0.01585kg/kg of dry air

Now

m_1h_1+m_2h_2=m_3h_3

m_1C_pT_1+m_2C_pT_2=m_3C_pT_3

m_1T_1+m_2T_2=m_3T_3

8\cdot 36+10\cdot 12=18\cdot T_3

T_3=22.67^{\circ}C

From Psychometric chart

at t=22.67^{\circ}C & \omega _3=0.01585 kg/kg of dry air

relative humidity ratio \phi =0.89 or 89\%

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Suppose the object complete 1 revolution within time t. The angular distance is 2π rad. Its angular velocity is 2π/t

The distance it covered is its circumference, which is 2πr, and so the speed is 2πr/t

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3 years ago
A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a directio
Bumek [7]

Answer:

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U - speed of primed frame with respect to the unprimed frame

Here we have:

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U =  -20 m/s        speed of primed (rest) frame with respect to moving frame

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What can you say about the magnitudes of the forces that the balloons exert on each other?
maxonik [38]

Answer:

F_G=G. \frac{m_1.m_2}{R^2} gravitational force

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Explanation:

The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.

The Mutual force of gravitational pull that they exert on each other can be given as:

F_G=G. \frac{m_1.m_2}{R^2}

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m_1\ \&\ m_2 are the masses of individual balloons

R= the radial distance between the  center of masses of the balloons.

But when  there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.

Given as:

F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}

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3 0
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