C. Aluminum (Al) oxidized, zinc (Zn) reduced
<h3>Further explanation</h3>
Given
Metals that undergo oxidation and reduction
Required
A galvanic cell
Solution
The condition for voltaic cells is that they can react spontaneously, indicated by a positive cell potential.
or:
E ° cell = E ° reduction-E ° oxidation
For the reaction to occur spontaneously (so that it E cell is positive), the E° anode must be less than the E°cathode
If we look at the voltaic series:
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The standard potential value(E°) from left to right in the voltaic series will be greater, so that the metal undergoing an oxidation reaction (acting as an anode) must be located to the left of the reduced metal (as a cathode)
<em />
From the available answer choices, oxidized Al (anode) and reduced Zn (cathode) are voltaic/galvanic cells.
Answer:
They form a covalent bond
1.
-Water levels are dangerously high for wildlife and humans.
-Animals seem to be lost, like the cow and the sheep especially.
2.
-There are not many trees near the water, meaning less areas for wildlife to live.
-There is not much wildlife in general.
Inferences
1. The wildlife shown will move relocate and adapt to another area.
2. Industry — emissions are visible in top left— will continue to hurt the environment. CO2 emissions will increase.
Good luck!
Answer:
9.4
Explanation:
The equation for the reaction can be represented as:
+ 
⇄ 
The ICE table can be represented as:
+ 
⇄
Initial 0.27 0.49 0.0
Change -x -2x x
Equilibrium 0.27 - x 0.49 -2x x
We can now say that the concentration of at equilibrium is x;
Let's not forget that at equilibrium = 0.11 M
So:
x = [] = 0.11 M
[] = 0.27 - x
[] = 0.27 - 0.11
[] = 0.16 M
[] = (0.49 - 2x)
[] = (0.49 - 2(0.11))
[] = 0.49 - 0.22
[] = 0.27 M
![K_C = \frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_C%20%3D%20%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
= 9.4
∴ The equilibrium constant at that temperature = 9.4
