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RUDIKE [14]
3 years ago
5

Difference between hygroscopic and deliquescent substance with of each​

Chemistry
2 answers:
iVinArrow [24]3 years ago
7 0

Answer:

The water soluble substance which absorb moisture from the air and then dissolve on the absorbed moisture to change into liquid taste are called deliquescent substances whereas the substances which absorb moisture from air but do not change their state are called hygroscopic substances.

melamori03 [73]3 years ago
5 0

Answer:

Hygroscopic substances absorb moisture from the air but do not dissolve in it, whereas substance that undergo deliquescence dissolves in the water vapour that is absorbed from the air, forming a liquid solution

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How many moles are in 29.5 grams of Ax?
JulsSmile [24]

The number of moles present in 29.5 grams of argon is 0.74 mole.

The atomic mass of argon is given as;

Ar = 39.95 g/mole

The number of moles present in 29.5 grams of argon is calculated as follows;

39.95 g ------------------------------- 1 mole

29.5 g ------------------------------ ?

= \frac{29.5}{39.95} \\\\= 0.74 \ mole

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.

<em>"Your question seems to be missing the correct symbol for the element" </em>

Argon = Ar

Learn more here:brainly.com/question/4628363

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2 years ago
Dessert biomes have all of these EXCEPT-
Dmitry_Shevchenko [17]
Answer: B). little wind


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7 0
3 years ago
Together oxygen and nitrogen comprise what percentage of the atmosphere
Charra [1.4K]
Oxygen is 21% and nitrogen is 78% so combined is 99%
5 0
3 years ago
A sample of methane gas has a volume of 355 mL at 25.0°C and 2414 mm Hg. If the temperature is raised to 100.°C and the pressure
Drupady [299]

Answer:

23019

Explanation:

5 0
3 years ago
Read 2 more answers
If iodine-131 has a half-life of 8 days, how much of a 64.0 g sample of iodine-131 will remain after 32 day?
Mariulka [41]

Answer:

4 g OF IODINE-131 WILL REMAIN AFTER 32 DAYS.

Explanation:

Half life (t1/2) = 8 days

Original mass (No) = 64 g

Elapsed time (t) = 32 days

Mass remaining (Nt) = ?

Using the half life equation we can obtain the mass remaining (Nt)

Nt = No (1/2) ^t/t1/2

Substituting the values, we have;

Nt = 64 * ( 1/2 ) ^32/8

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Nt = 64 * 0.0625

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So therefore, 4 g of the iodine-131 sample will remain after 32 days with its half life of 8 days.

8 0
3 years ago
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