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Rama09 [41]
3 years ago
12

Reactants are substances that?

Chemistry
1 answer:
RSB [31]3 years ago
4 0
A substance that undergoes change during a reaction, usually from coming in contact with another substance
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Enter ionic and net equations: feso4(aq)+ na3po4(aq) arrow fe3(po4)2(s)+na2so4(aq)
stepan [7]

Answer:

<em> ionic equation : </em>3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

<em> net ionic equation: </em>3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

Explanation:

The balanced equation is

3FeSO4(aq)+ 2Na3PO4(aq) → Fe3(PO4)2(s)+ 3Na2SO4(aq)

<em>Ionic equations: </em>Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions . Indicate the correct formula and charge of each ion. Indicate the correct number of each ion . Write (aq) after each ion .Bring down all compounds with (s), (l), or (g) unchanged. The coefficents are given by the number of moles in the original equation

3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

<em>Net ionic equations: </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions, it means the repeated ions that are present.  Write the "leftovers" as the net ionic equation.

3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

6 0
3 years ago
How many moles are found in 10.5 g of Pb?
deff fn [24]

Answer:

Number of moles = 0.05 mol

Explanation:

Given data:

Mass of Pb = 10.5 g

Number of moles of Pb = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of Pb is 207.2 g/mol.

Now we will put the values in formula.

Number of moles = 10.5 g/207.2 g/mol

Number of moles = 0.05 mol

6 0
3 years ago
When
svp [43]

Answer:

  • <em><u>hdkdjfjhdakdhevghggggfdffggggfggcdhxgjcfogogi</u></em>
6 0
2 years ago
The free energy of formation of nitric oxide, NO, at 1000 K (roughly the temperature in an automobile engine during ignition) is
Assoli18 [71]

<u>Answer:</u> The value of K_p for the chemical equation is 8.341\times 10^{-5}

<u>Explanation:</u>

For the given chemical equation:

N_2(g)+O_2(g)\rightarrow 2NO(g)

To calculate the K_p for given value of Gibbs free energy, we use the relation:

\Delta G=-RT\ln K_p

where,

\Delta G = Gibbs free energy = 78 kJ/mol = 78000 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = temperature = 1000 K

K_p = equilibrium constant in terms of partial pressure = ?

Putting values in above equation, we get:

78000J/mol=-(8.314J/Kmol)\times 1000K\times \ln K_p\\\\Kp=8.341\times 10^{-5}

Hence, the value of K_p for the chemical equation is 8.341\times 10^{-5}

4 0
3 years ago
The atomic weight of an atom is the sum of the mass of the particles in the nucleus of the atom. These particles are called?
Ludmilka [50]

Answer:

c) neutrons and protons

Explanation:

The nucleus of the atom contains only neutrons and protons. Electrons are not in the nucleus but outside the nucleus in 'atomic orbitals'.

5 0
2 years ago
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