Answer:
1.87 J
Explanation:
q = c x m x (T2-T1)
c- specific heat of water (4.186 j/g.C)
q = 4.186 x 0.5137 x 0.871 = 1.87 J
Answer:
150 g of potassium contained 3.8 moles of potassium.
Explanation:
Given data:
Mass of potassium = 150 g
Moles of potassium = ?
Solution:
Number of moles = mass/ molar mass
Molar mass of potassium = 39 g/mol
Now we will put the values in formula:
Number of moles = mass/ molar mass
Number of moles = 150 g/ 39 g/mol
Number of moles = 3.8 mol
150 g of potassium contained 3.8 moles of potassium.
Answer:inform the lab instructor and get instructions
Explanation:
If you come across a chemical in the laboratory which has been wrongly labelled, do not be quick to dilute it or take any further action. The laboratory instructor who may have prepared the reagent himself or has better knowledge about the reagent should be contacted immediately so that he/she can give you instructions about what to do with the wrongly labelled reagent.
1. Chemical
2. Physical
1. Exothermic
2. Endothermic
1. Chemical
2. Physical
