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RoseWind [281]
1 year ago
14

What would happen if the atmosphere consisted of pure oxygen.

Physics
1 answer:
mezya [45]1 year ago
5 0

Answer:

Then our fires would become massive.

Explanation:

Hope this helps

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1. What do you notice from the picture?<br>2. Did anyone get the correct answer? ​
Fudgin [204]

Answer:

1. I notice nothing because is no picture it probably didnt work

2. idk

6 0
3 years ago
All waves transfer____. Energy weight velocity mass
Katarina [22]

I believe the answer is energy

5 0
3 years ago
Example 7.3
marysya [2.9K]

Answer:

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4 0
2 years ago
A 92kg astronaut and a 1200kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, giving
Harman [31]

Answer:

13.7m

Explanation:

Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.

After the push

m_av_a + m_sv_s = 0

Where m_a = 92kg is the mass of the astronaut, m_s = 1200kg is the mass of the satellite, v_s = 0.14 m/s is the speed of the satellite. We can calculate the speed v_a of the astronaut:

v_a = \frac{-m_sv_s}{m_a} = \frac{-1200*0.14}{92} = -1.83 m/s

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be

d = vt = 1.83 * 7.5 = 13.7 m

4 0
3 years ago
There's an electric field in some region of space that doesn't change with position. An electron starts moving with a speed of 2
tangare [24]

Answer:

Explanation:

Given

speed of Electron u=2\times 10^7\ m/s

final speed of Electron v=4\times 10^7\ m/s

distance traveled d=1.2\ cm

using equation of motion

v^2-u^2=2as

where v=Final velocity

u=initial velocity

a=acceleration

s=displacement

(4\times 10^7)^2-(2\times 10^7)^2=2\times a\times 1.2\times 10^{-2}

a=5\times 10^{16}\ m/s^2

acceleration is given by a=\frac{qE}{m}

where q=charge of electron

m=mass of electron

E=electric Field strength

5\times 10^{16}=\frac{1.6\times 10^{-19}\cdot E}{9.1\times 10^{-31}}

E=248.3\ kN/C                

5 0
3 years ago
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