Answer:
The downwards acceleration is 3.53 m/s2.
Explanation:
Let the true weight is m g.
The reading of the balance, R = 0.64 mg
Let the acceleration is a.
As the apparent weight is less than the true weight so the elevator goes down wards with some acceleration.
Use Newton's second law
m g - R = m a
m g - 0.64 m g = m a
0.36 g = a
a = 3.53 m/s2
To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations
Work done to upward the object
Horizontal Force applied while carrying 10m,
Height descended in setting the child down
For full time, assuming that the total value of work is always expressed in terms of its symbol, it would be zero, since at first it performs the same work that is later complemented in a negative way.
Answer:
40000 N
Explanation:
Force: This cam be defined as the product of mass and acceleration.
From the question,
The braking force of the lorry will be the same in magnitude as the force at which the lorry is moving.
F = ma..................... Equation 1
Where m = mass of the lorry, a = acceleration/deceleration of the lorry.
Given: m = 5000 kg, a = 8 m/s²
Substitute these values into equation 1
F = 5000(8)
F = 40000 N
D is the answer because your body can do that in all the 7 location where the heat goes in your body in 2,3, OR 5-6 days
