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SVETLANKA909090 [29]
3 years ago
13

An object moving 20 m/s

Physics
1 answer:
yan [13]3 years ago
7 0

Answer:

<u>We are given:</u>

initial velocity (u) = 20m/s

acceleration (a) = 4 m/s²

time (t) = 8 seconds

displacement (s) = s m

<u />

<u>Solving for Displacement:</u>

From the seconds equation of motion:

s = ut + 1/2 * at²

replacing the variables

s = 20(8) + 1/2 * (4)*(8)*(8)

s = 160 + 128

s = 288 m

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Calculate the wavelength associated with an electron with energy 2000 eV.

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3 years ago
A solid cylinder of uniform density of 0.85 g/cm3 floats in a glass of water tinted light blue by food coloring.
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Each side has to have at least 44 horses

F61160 N. This is further explained below.

<h3>What is the force?</h3>

Generally, We are only interested in the component that operates horizontally since the vertical components all cancel each other out. The pressure difference works on the hemisphere to generate a normal force all over the surface, but we are only concerned with that force's horizontal component. This may be determined by supposing the hemispheres to be two flat circular plates of the same radius as the hemispheres that have been forced together.

Therefore, force is equal to pressure multiplied by area, which is

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Therefore, each side has to have at least 44 horses

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2 years ago
A three-wheeled car moving along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed
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Answer:

(a) Total time = 105.5 sec

(b)average speed = 31.26 m/sec

Explanation:

We have given that three-wheeled car starts from rest that initial velocity u = 0 m/sec

Final velocity = 35 m/sec

Acceleration a=2m/sec^2

According to first law of motion we know that v = u+at

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After this car travels 83 sec at a constant speed and after that it takes 5 sec additional time to stop

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(b) Total distance traveled during first 17.5 sec

s=ut+\frac{1}{2}at^2=0\times 17.5+\frac{1}{2}\times 2\times 17.5^2=306.25m

Distance traveled in 83 sec with with velocity of 35 m/sec = 35\times 83=2905m

For next 5 second

Initial velocity u = 35 m/sec

Final velocity = 0 as finally car stops

So a=\frac{v-u}{t}=\frac{0-35}{5}=-7m/sec^2

Distance traveled s=ut+\frac{1}{2}at^2=35\times 5+\frac{1}{2}\times -7\times 5^2=87.5m

So total distance traveled = 306.25+2905+87.5 = 3298.75 m

Total time = 105.5 sec

So average speed =\frac{total\ distance}{total\ time }=\frac{3298.75}{105.5}=31.26m/sec

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