To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as
, the relation with the final volume as
![V_2 = V_1 +0.163\% V_1](https://tex.z-dn.net/?f=V_2%20%3D%20V_1%20%2B0.163%5C%25%20V_1)
![V_2 = V_1 +0.00163V_1](https://tex.z-dn.net/?f=V_2%20%3D%20V_1%20%2B0.00163V_1)
![V_2 = 1.00163V_1](https://tex.z-dn.net/?f=V_2%20%3D%201.00163V_1)
Initial temperature = ![21.1\°C](https://tex.z-dn.net/?f=21.1%5C%C2%B0C)
Let T be the temperature after expanding by the formula of volume expansion
we have,
![V_2 = V_1 (1+\gamma \Delta t)](https://tex.z-dn.net/?f=V_2%20%3D%20V_1%20%281%2B%5Cgamma%20%5CDelta%20t%29)
Where
is the volume coefficient of copper ![5.1*10^{-5}/C](https://tex.z-dn.net/?f=5.1%2A10%5E%7B-5%7D%2FC)
![1.00163V_1 = V_1(1+\gamma(T-21.1\°))](https://tex.z-dn.net/?f=1.00163V_1%20%3D%20V_1%281%2B%5Cgamma%28T-21.1%5C%C2%B0%29%29)
![1.00163 = 1+5.1*10^{-5}(T-21.1\°)](https://tex.z-dn.net/?f=1.00163%20%3D%201%2B5.1%2A10%5E%7B-5%7D%28T-21.1%5C%C2%B0%29)
![0.00163 = 0.000051T-0.0010761](https://tex.z-dn.net/?f=0.00163%20%3D%200.000051T-0.0010761)
![T = 53.0608\°C](https://tex.z-dn.net/?f=T%20%3D%2053.0608%5C%C2%B0C)
Therefore the temperature is 53.06°C
Molecular Geometry is the three-dimensional structure or arrangement of atoms in a molecule.
Hey there
how are u..................................................
The weight is 45 N, because the three chains hold the sign, and each contributes 15 N.
Notice that the mass would be the weight/acceleration of gravity, m = 45/9.8 kg. But they ask the weight (force, so Newtons)