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Alenkinab [10]
2 years ago
11

A practical machine cannot be 100% efficient? please give me the answer.​

Physics
2 answers:
lara31 [8.8K]2 years ago
8 0

Answer: yes it cannot be 100% efficient

Explanation:

only an ideal machine with 0 friction can have 100 percent efficiency

RSB [31]2 years ago
3 0

\huge\color{Basic}{\boxed{\tt{answer}}}

<h2>A practical machine cannot be 100% efficient? </h2>

  • IF THE CHOICES ARE TRUE OR FALSE THEN U GO
  • The answer is false a machine cannot be 100 percent efficient because the output of a machine is always less than input. (correct me if I’m wrong)

<h2>Have a great day<3</h2>
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Answer:

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3 years ago
A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has
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3.07 m/s

Explanation:

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7 0
3 years ago
PLEASE HELP!
Harman [31]
Hey user!

your answer is here..

correct option is A. steel

we know that sounds travel faster in solid as compared to gas and liquids. in gas the molecules are very loosely packed and there is lot of space between so it takes more time to pass sound from each other. and in liquid, the molecules are closer as compared to gas hence it will be little faster and in solid, the molecules are very tightly packed so it will be the fastest. and among these options, steel is the only solid so the speed of sound in steel will be the fastest.

and note that the closer the molecules are to each other ( tightly packed ) makes the bond also tighter and less time to pass sound.

cheers!!
8 0
3 years ago
A standing wave pattern is created on a string with mass density μ = 3.4 × 10-4 kg/m. A wave generator with frequency f = 61 Hz
uranmaximum [27]

Answer:

1) λ = 0.413 m , 2)v = 25,213 m / s , 3)  T = 0.216 N , 4) m = 22.04 10-3 kg

Explanation:

1) The resonance occurs when the traveling wave bounces at the ends and the two waves are added, the ends as they are fixed have a node, the wavelength and the length of the string are related

         λ = 2L / n               n = 1, 2, 3 ...

In this case L = 0.62 m and n = 3

Let's calculate

        λ = 2 0.62 / 3

        λ = 0.413 m

2) the velocity related to wavelength and frequency

      v =  λ f

      v = 0.413 61

      v = 25,213 m / s

3) let's use the equation

     v = √T /μ

     T = v² μ

     T = 25,213² 3.4 10⁻⁴

     T = 0.216 N

4) the rope tension is proportional to the hanging weight

      T-W = 0

     T = W

    W = m g

    m = W / g

    m = 0.216 / 9.8

    m = 22.04 10-3 kg

5) n = 2

     λ = 2 0.62 / 2

     λ = 0.62 m

6) v =  λ f

     v = 0.62 61

     v = 37.82 m / s

7) T = v² μ

   T = 37.82² 3.4 10⁻⁴

   T = 0.486 N

8) m = W / g

   m = 0.486 / 9.8

   m = 49.62 10⁻³ kg

9) n = 1

    λ = 2 0.62

    λ = 1.24 m

    v = 1.24 61

    v = 75.64 m / s

    T = v² miu

    T = 75.64² 3.4 10⁻⁴

    T = 2.572 10⁻² N

    m = 2.572 10⁻² / 9.8

    m = 262.4 10⁻³ kg

5 0
3 years ago
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