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2 years ago

What is the acceleration of a rocket that speeds up from 50 m/s to 1000 m/s in 3 seconds?

Physics

1 answer:

Zepler [3.9K]2 years ago

8 0

Answer:

= 316.67 m/s^2

Explanation:

Acceleration formula =

A = $\frac{V_{f} - V_{i} }{t}$

$A = \frac{1000 - 50}{3}$

= $\frac{950}{3}$

= 316.67 m/s^2

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In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect o

Marrrta [24]

Answer:

<h2>Case i) if $\omega L > \frac{1}{\omega c}$ </h2><h2>So initially if the circuit is inductive in nature then its net impedance will decrease after this</h2><h2>Case ii) if $\omega L < \frac{1}{\omega c}$ </h2><h2>So initially if the circuit is capacitive in nature then its net impedance will increase after this</h2>

Explanation:

As we know that the impedance of the circuit is given as

$z = \sqrt{(\omega L - \frac{1}{\omega c})^2 + R^2}$

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

$c_{eq} = c_1 + c_2$

so it is

$c_{eq} = 2c$

now we have

$z = \sqrt{(\omega L - \frac{1}{2\omega c})^2 + R^2}$

Case i) if $\omega L > \frac{1}{\omega c}$

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if $\omega L < \frac{1}{\omega c}$

So initially if the circuit is capacitive in nature then its net impedance will increase after this

7 0

3 years ago

Why is tungsten used as a filament in a bulb?

Viktor [21]

Answer:

because of tungsten's high melting point

Explanation:

7 0

2 years ago

The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P

bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

$a=\dfrac{P}{m}$

$a=\dfrac{181\ N}{68\ kg}$

$a=2.67\ m/s^2$

(c) P = 352 N

$a=\dfrac{P}{m}$

$a=\dfrac{352\ N}{68\ kg}$

$a=5.17\ m/s^2$

Hence, this is the required solution.

5 0

3 years ago

: A 70 kg man and a 12 kg sled are on the frictionless ice of a frozen lake, 25 m apart but connected by a rope of negligible ma

e-lub [12.9K]

Answer:

$x_1 = 3.74m$

Explanation:

given,

mass of man = 70 kg

mass of sled = 12 kg

F = m a_s

$a_s = \dfrac{F}{m}$

$a_s = \dfrac{8.2}{12}$

$a_s = 0.68\ m/s^2$

$F = m a_m$

$a_m = \dfrac{F}{m}$

$a_m = \dfrac{8.2}{70}$

$a_m = 0.12\ m/s^2$

$x_1+x_2 = 25$

$\dfrac{1}{2}a_ct^2+ \dfrac{1}{2}a_mt^2 = 25$

$(a_c+a_m)t^2=50$

$(0.12+0.68)t^2=50$

$t = \sqrt{\dfrac{50}{0.8}}$

t = 7.90 s

$x_1 = \dfrac{1}{2}a_ct^2$

$x_1 = 0.5\times 0.12 \times 7.90^2$

$x_1 = 3.74m$

5 0

3 years ago

A rocket of mass m is to be launched fromplanet X, which has a mass M and a radius R. What is the minimum speed that the rocket

Sunny_sXe [5.5K]

Answer:

The minimum speed = $\sqrt{\frac{2GM}{R} }$

Explanation:

The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.

The minimum speed can be determined by;

Escape velocity = $\sqrt{\frac{2GM}{R} }$

where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.

If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.

7 0

2 years ago