This is a very wierd question but I will answer.It is A
Hope I helped
Answer:
a) v=2.743m/s
b) 
c) T=2.543N
Explanation:
First, calculate the height of the ball at the starting point:


At this point, just in the moment the ball is released, all the energy of the system is potencial gravitational energy. When it is at the bottom all the potencial energy is transformed into kinetic energy:

Solving for v:

if h is the height loss: (l-y')
v=2.743m/s
The centripetal acceleration is the acceleration caused by the tension force exercised by the string, and is pointing outside of the trayectory path (at the lowest point, directly dawn):


To calculate tension, just make the free body diagram of forces in the ball, noticing the existence of the centripetal acceleration:

Answer:
Explanation:
so filling in:
so to 2 sig figs (which is actually not accurate, but oh well...)
KE = 450000 J
If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:
450000 = (1000)(9.8)h so

Answer:
F = - 6.95 10⁻² j^ N
Explanation:
The force on a wire carrying current through a magnetic field is
F = i L x B
The bold letters indicate vectors, as the wire is in the positive Z axis and the magnetic field in the negative x axis, the force must be in the negative y axis
the force module
F = i LB
that there is 90º between the two vectors and the sin 90 = 1
let's calculate
F = 4.9 3.3 10⁻² 0.43
F = 6.95 10⁻² N
the force vector is
F = - 6.95 10⁻² j^ N