1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina86 [1]
2 years ago
7

Map.

Physics
1 answer:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

The object has decreasing acceleration and decreasing velocity.

You might be interested in
Practical steam engines utilize 450ºC steam, which is later exhausted at 270ºC.
Naily [24]

(a) 0.249 (24.9 %)

The maximum efficiency of a heat engine is given by

\eta = 1-\frac{T_C}{T_H}

where

Tc is the low-temperature reservoir

Th is the high-temperature reservoir

For the engine in this problem,

T_C = 270^{\circ}C+273=543 K

T_H = 450^{\circ}C+273=723 K

Therefore the maximum efficiency is

\eta = 1-\frac{T_C}{T_H}=1-\frac{543}{723}=0.249

(b-c) 0.221 (22.1 %)

The second steam engine operates using the exhaust of the first. So we have:

T_H = 270^{\circ}C+273=543 K is the high-temperature reservoir

T_C = 150^{\circ}C+273=423 K is the low-temperature reservoir

If we apply again the formula of the efficiency

\eta = 1-\frac{T_C}{T_H}

The maximum efficiency of the second engine is

\eta = 1-\frac{T_C}{T_H}=1-\frac{423}{543}=0.221

8 0
3 years ago
Frying an egg conduction convention radiation
Allushta [10]

Answer:

frying an egg is conduction because the pan is touching the stove and the pan is touching the eggs

Explanation:

4 0
3 years ago
A satellite’s velocity is 30000m/s. After 60 secs, it’s velocity shows to 15000m/a. What is the satellite’s acceleration?
Orlov [11]

Answer:

Acceleration = 9 × 10^5 m/s^2 ( deceleration )

Explanation:

From the first equation of motion:

V = u + at

15000 = 30000 + 60a

a = ( 15000-30000)/60

a = 9 × 10^5 m/s^2

4 0
2 years ago
One principle of environmental law and policy in the U.S. is to make polluters pay . True or false ?
crimeas [40]
In a way it’s true because you can get a ticket for getting caught littering
5 0
3 years ago
A 2.2-kg block slides on a horizontal surface with a speed of v=0.80m/s and an
mina [271]

Answer:

μ = 0.33

Equal to 3.2 m/s²

Explanation:

Draw a free body diagram of the block.  There are three forces:

Normal force N pushing up.

Weight force mg pulling down.

Friction force Nμ pushing opposite the direction of motion.

Sum of forces in the y direction.

∑F = ma

N − mg = 0

N = mg

Sum of forces in the x direction.

∑F = ma

Nμ = ma

Substitute.

mgμ = ma

μ = a/g

μ = (3.2 m/s²) / (9.8 m/s²)

μ = 0.33

As found earlier, the acceleration is a = gμ.  Since g and μ are constant, a is also constant, so it does not change with velocity.

5 0
3 years ago
Other questions:
  • Most of the stars in the Milky Way will end their lives as
    5·2 answers
  • A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet
    12·1 answer
  • What is the half life of Strontium-90? Explain your answer
    11·2 answers
  • A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work
    6·1 answer
  • The electric force between two charged objects of charge +Q0 that are separated by a distance R0 is F0. The charge of one of the
    12·1 answer
  • The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is
    12·1 answer
  • If you disconnect the wires from the battery and then reconnect them at the opposite ends of the battery, how does that change t
    15·1 answer
  • Three-fourths of the elements on the
    8·1 answer
  • 1. Why did Asteroid 2019 OK cause concern among scientists? * The asteroid was not detected until it was extremely close to Eart
    15·1 answer
  • Which image shows a nonrenewable resource?<br><br> sun<br> fire<br> can<br> plant
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!