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1 year ago

What is the source of the forces that move the tectonic plates along this plate

Chemistry

2 answers:

geniusboy [140]1 year ago

8 0

The source of the forces that move the tectonic plates along this plate

boundary is the convection current in the mantle. Hence, the correct

option in option (B)

<h3>What are Tectonic plates ?</h3>

Tectonic plates refers to the Spheres that are found in the uppermost Mantle of the Earth .

The Tectonic plates are also called the Litosphere .

The Motion of the Plates about the axis causes the Tectonic demarcations which are Know as the

Convergent

Divergent

Transform

Now these Plate are formed by the Convection of Currents in the Earths's Mantle

That is, the Dynamics of Current in and around the Earths Mantle brings about the tectonic plates

Hence the the correct option in option (B)

Learn more about tectonic plates Here ;

brainly.com/question/15476626

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padilas [110]1 year ago

7 0

Convection currents in the mantle is the source of the forces that move the tectonic plates along this plate boundary and is denoted as option B.

<h3>What is Convection?</h3>

This is referred to the process of heat transfer in a fluid such as gases and liquids.

The convection currents in the mantle is responsible for the force present in the tectonic plates.

Read more about Convection here brainly.com/question/9382711

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How are renewable fuels different from fossil fuels

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Taya2010 [7]

Answer:

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3 years ago

What gives the gem amethyst its purplish color?

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3 years ago

What is the final temperature of a 34.2 g of water initially at 282 K that has been heated with 2.71 kJ of energy?

lana66690 [7]

Answer: The final temperature of copper is

Further explanation:

The property is a unique feature of the substance that differentiates it from the other substances. It is classified into two types:

1. Intensive properties:

These are the properties that depend on the nature of the substance. These don't depend on the size of the system. Their values remain unaltered even if the system is further divided into a number of subsystems. Temperature, refractive index, concentration, pressure, and density are some of the examples of intensive properties.

2. Extensive properties:

These are the properties that depend on the amount of the substance. These are additive in nature when a single system is divided into many subsystems. Mass, enthalpy, volume, energy, size, weight, and length are some of the examples of extensive properties.

Specific heat is the amount of heat required to increase the temperature of any substance per unit mass. Specific heat capacity is also known as mass specific heat. Its SI unit is Joule (J).

The formula to calculate the heat energy of copper is as follows:

…… (1)

Here,

Q is the amount of heat transferred.

m is the mass of copper.

c is the specific heat of copper.

is the change in temperature of copper.

Rearrange equation (1) to calculate the temperature change.

…… (2)

The value of Q needs to be converted into J. The conversion factor for this is,

So the value of Q can b calculated as follows:

The value of Q is 4689 J.

The value of m is 34.2 g.

The value of c is .

Substitute these values in equation (2).

The temperature change can be calculated as follows:

…… (3)

Here,

is the change in temperature.

is the final temperature.

is the initial temperature.

Rearrange equation (3) to calculate the final temperature.

…… (4)

The value of is .

The value of is

Substitute these values in equation (4).

So the final temperature of copper is .

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3 years ago

if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?

skelet666 [1.2K]

<span>We can use the heat equation,
Q = mcΔT </span>

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>

Density = mass / volume

The density of water = 0.997 g/mL

<span>Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL</span>

Specific heat capacity of water = 4.186 J<span>/ g °C.</span>

Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
T = 1.04 °C + 23 °C
T = 24.04 °C

Hence, the final temperature of the water is 24.04 °C.

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3 years ago