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Dimas [21]
3 years ago
7

The equation that describes the process of photosynthesis

Chemistry
2 answers:
Alexandra [31]3 years ago
7 0
The last choice is the equation for photosynthesis
notsponge [240]3 years ago
7 0

the last choice is the equation for photosynthesis

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What is the chemical formula for the compound formed between chromium(iii) and the sulfate ion
Anastasy [175]
Cr2(SO4)3 is the formula
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How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?
allochka39001 [22]

The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

 

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

 

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

 

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

<span>volume Na2S = 0.0212 L = 21.2 mL</span>

6 0
3 years ago
What is the acceleration object velocity of +25m/s to rest in 5.0 s
Irina-Kira [14]

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (<em>a</em>) is

a = \frac{v_{f}- v_{i}}{t}

v_{f} = 25 m·s⁻¹;  v_{i} = 0; t = 5.0 s

∴ a = \frac{0-25}{5.0} = -5.0 m·s⁻²

The negative sign tells you that the object is <em>slowing down</em>, i.e., it is <em>decelerating</em>.


4 0
3 years ago
Which organ detects stimuli from the environment and is part of the nervous system?
sleet_krkn [62]

It's the eye because it's the organ of sight

5 0
3 years ago
How many moles are in 3.113 g of Au?Molar mass of Au=197 g/mol
SVEN [57.7K]
<h3>Answer:</h3>

0.0157 g Au

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.113 g Au

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 197.87 g/mol

<u>Step 3: Convert</u>

<u />3.113 \ g \ Au(\frac{1 \ mol \ Au}{197.87 \ g \ Au} ) = 0.015733 g Au

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.015733 g Au ≈ 0.0157 g Au

3 0
3 years ago
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