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enot [183]
3 years ago
5

A man stands on the top of the hill at point A and then runs down at point B. What kind of energy conversion occurs from point A

to point B?
- kinetic to heat
- elastic potential to kinetic
- gravitational potential to kinetic
- kinetic to elastic potential
- kinetic to gravitational potential

Chemistry
2 answers:
melisa1 [442]3 years ago
7 0
Kinetic to heat I think
Yanka [14]3 years ago
3 0

Answer:

The answer is gravitational potential to kinetic energy

Explanation:

On the top of the hill there is height and distance to fall and gravity will have more potential. For instance gravity is represented by 9.81 m/s^2 which means that it will accelerate. And when on top of a hill there is more time to accelerate, and that is it's gravitational potential. Then when going down the hill that potential energy is transformed into kinetic energy (which is defined as a body in motion). Hence, the man from the top of the hill, point A, to moving down the hill, point B, starts with gravitational potential at point A, then that potential is transferred into kinetic energy at point B.

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Which subatomic particle gives off visible light when it drops back down to a lower energy state?
icang [17]

Answer:

Option C = electron

Explanation:

Electrons are responsible for the production of colored light.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e-

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

How electrons produce the colored light:

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When the energy is provided to the atom the electrons by absorbing the energy jump to the higher energy levels. This process is called excitation. The amount of energy absorbed by the electron is exactly equal to the energy difference of orbits.

De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

Other process may involve,

Fluorescence:

In fluorescence the energy is absorbed by the electron having shorter wavelength and high energy usually of U.V region. The process of absorbing the light occur in a very short period of time i.e. 10 ∧-15 sec. During the fluorescence the spin of electron not changed.

The electron is then de-excited by emitting the light in visible and IR region. This process of de-excitation occur in a time period of 10∧-9 sec.

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5 0
3 years ago
PLEASE HELP! Class is almost ending, I don't want to repeat.
nikklg [1K]
ANSWERS:

1. 2KClO_{3} ⇒ 2KCl + 3O_{2}

2. H_{2}  C_{2} O_{4}  + 2NaOH ⇒ Na_{2}  C_{2} O_{4}  + 2 H_{2} O

3. 2 C_{10}  H_{22} +  31O_{2} ⇒ 20C O_{2} + 22 H_{2} O

4. 4 H_{2} + Fe_{3} O_{4} ⇒ 3Fe +4 H_{2} O

5. 4P + 5 O_{2} ⇒ 2 P_{2}  O_{5}


I have attached my work for 1-3. I would like to see if you can get 4 and 5 on your own. but, if you are struggling/copnfused please let me know in the comments! :)

6 0
3 years ago
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