All categories

3 years ago

What is wrong with this model of the atom.

Chemistry

1 answer:

sp2606 [1]3 years ago

8 0

Answer:

A. The neutrons and electrons are in the wrong place.

Explanation:

The atom's nucleus contains both protons and neutrons, whilst the electrons are arranged in shells around the nucleus.

You might be interested in

You can supply activation energy to begin a reaction by _____.

ehidna [41]

If I remember correctly, you would have to heat the reaction beaker over a burner..

I apologize if I'm wrong

3 0

3 years ago

Read 2 more answers

___________ have a charge of +1.

stiv31 [10]

Answer:

B) Protons

Explanation:

A proton has positive charge of 1.
Electrons are the negatively charged particles of atom.
An atom consists of a positively charged nucleus surrounded by one or more negatively charged particles called electrons
To find the ionic charge of an element you'll need to consult your Periodic Table. On the Periodic Table metals (found on the left of the table) will be positive. Non-metals (found on the right) will be negative.

3 0

3 years ago

Chlorine gas will effuse more quickly than ammonia gas. a. true b. false

rjkz [21]

This statement is false due to the fact that the ammonia gas has the lower molar mass.
~Hope this helps

8 0

3 years ago

Two oxide of sulphur,A and B were analyzed and the results obtained showed that in oxide A,3.50g of sulphur combined with 6.00g

Nimfa-mama [501]

Answer:

See Explanaton

Explanation:

The law of multiple proportions states that when two same elements form more than a compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers.

<u>Oxide A</u>

3.50g of sulphur combined with 6.00g of oxygen

Oxygen:Sulphur = 6 : 3.5

<u>Oxide B</u>

2.80g of sulphur combined with 9.55g

Oxygen : Sulphur = 9.55 : 2.8

Therefore:

The ratio of Oxygen to Sulphur in Oxides A and B is:

$\dfrac{\text{Oxygen}}{\text{Sulphur}} \implies \dfrac{6}{3.5}:\dfrac{9.55}{2.8} = \dfrac{1.7}{1}:\dfrac{3.4}{1}=1:2$

Ratio of Oxygen=1:2

There is exactly twice in Oxide B as in Oxide A.

This result illustrates the law of multiple proportions.

5 0

3 years ago

citric acid has an acid dissociation constant of 8.4 x 10^-4 it would be most effective for preparation of a buffer with a pH of

Sloan [31]

Answer:

(B) 3

Explanation:

Citric acid has an acid dissociation constant (Ka) of 8.4 × 10⁻⁴. When it forms a buffer with its conjugate base (citrate), we can calculate the pH using the Henderson-Hasselbalch's equation.

$pH=pKa+log\frac{[base]}{[acid]}$

The optimum range of pH is pKa ± 1. The pKa is -log Ka = -log (8.4 × 10⁻⁴) = 3.1. The buffer would be more effective for pH between 2.1 and 4.1, especially around 3.1. So the best choice is (B) 3.

5 0

3 years ago