Answer:
Molar concentration of CO₂ in equilibrium is 0.17996M
Explanation:
Based on the reaction:
NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)
kc is defined as:
kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>
As initial concentration of CO is 0.18M, the concentrations in equilibrium are:
[CO] = 0.18000M - x
[CO₂] = x
Replacing in (1):
4.0x10³ = x / (0.18000-x)
720 - 4000x = x
720 = 4001x
x = 0.17996
Thus, concentrations in equilibrium are:
[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵
[CO₂] = x = <em>0.17996M</em>
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Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>
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I hope it helps!
The reaction of sodium bromide with chlorine gas is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
<h3>What is sodium bromide?</h3>
Sodium bromide is an inorganic compound, white, crystalline with high melting point.
The reaction between halogens is redox reaction
Oxidation – 2Br⁻ ? Br₂ + 2e⁻ loss of electron.
Reduction – Cl₂ + 2e⁻ ? 2Cl⁻ gains of electron.
Thus, the correct option is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
Learn more about sodium bromide
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Answer:
For the following reaction, 8.00 grams of silicon tetrafluoride are allowed to react with 7.40 grams of water. silicon tetrafluoride (s) + water (l) hydrofluoric acid (aq) + silicon dioxide (s) What is the maximum amount of hydrofluoric acid that can be formed? grams What is the FORMULA for the limiting reagent? H2O What amount of the excess reagent remains after the reaction is complete? grams
3 moles of the diatomic green
--> p1=0.63 atm = 3×2 atoms
p2 is 6 moles of blue
p3 is 5 moles of orange
P-total (Pt) = p1 + p2 + p3
Pt = 0.63 + 0.63 + (0.63)(5)/6
Pt = 1.26 + 0.525 = 1.79 atm
<span>C3H7
The unknown compound consists of only carbon and hydrogen. The oxygen comes from the air. So you need to first determine the relative moles of hydrogen and carbon that are present in the CO2 and H2O. First, look up the molar masses of Carbon, Hydrogen, and Oxygen. Then determine the molar masses of CO2 and H2O.
Carbon = 12.0107
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of CO2
1 * 12.0107 + 2 * 15.999 = 44.0087
Molar mass of H2O
2 * 1.00794 + 1 * 15.999 = 18.01488
Number of moles of CO2
22.1 g / 44.0087 g/mol = 0.502173
Number of moles of H2O
10.5 g / 18.01488 g/mol = 0.582852
Since there's 1 carbon atom per CO2 molecule, there are 0.502173 moles of carbon.
Since there's 2 hydrogen atoms per H2O molecule, there are 2 * 0.582852 = 1.165703 moles of hydrogen.
Now we need to find a simple ratio of small integers that comes close to the ratio of 0.502173 / 1.165703 = 0.43079 to determine the empirical formula.
3/7 = 0.428571, an error of only 0.002219. The next closest ratio has an error of 0.013654, over 6 times larger.
So the empirical formula is C3H7</span>
