Answer:
The answer to your question is below
Explanation:
Metals lose electrons and Nonmetals gain them.
a. Ra is in group IIA it will lose electrons, the ion will be Ra⁺²
b. Br is in group VIIA it will gain electrons, the ion will be Br⁻¹
c. In is in group IIIA it will lose electrons, the ion will be In⁺³
d. Te is in group VIA it will gain electrons, the ion will be Te⁻²
e. Ca is in group IIA it will lose electrons, the ion will be Ca⁺²
f. As is in group VA it will gain electrons, the ion will be As⁻³
g. Al is in group IIlA it will lose electrons, the ion will be Al⁺³
h. Rb is in group IA it will lose electrons, the ion will be Rb⁺¹
Answer:
hello, i hope this helps.
Explanation:
1 - group
2 - period
3 - periodic table
4 - family
5 - octet rule
6 - valence electrons
Answer:
Path length is the overall distance traveled following the path of where the object travel. ... Displacement is the distance from the starting point of the object to its final point irregardless where it travels.
Ionic compounds are formed between oppositely charged ions.
A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).
To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.
First empirical formula of binary ionic compound is written between
First Formula would be 
Second empirical formula is between 
Second Formula would be 
Note : When the subscript are same they get cancel out, so
would be written as 
Third empirical formula is between 
Third Formula would be :
Forth empirical formula is between 
Forth Formula would be :
or 
Note- The subscript will be simplified and the formula will be written as
.
The empirical formula of four binary ionic compounds are : 