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MrRa [10]
3 years ago
5

What is the molar mass of a substance

Chemistry
2 answers:
rewona [7]3 years ago
5 0
The mass of an element in the periodic table
zheka24 [161]3 years ago
4 0

Molar mass of a molecule is the sum of the atomic mass of the individual elements in the molecule.  

Atomic mass of Pb = 207  amu

Atomic mass of N = 14  amu

Atomic mass of O = 16  amu

Here amu stands for atomic mass unit

Molar mass of Pb(NO₃)₂ = 207 + [14 + (16 x 3)] x 2  

                                         = 207 + 28 + (48) x 2 = 331 g/mol  

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How many grams of water at 50◦c must be added to 16 grams of ice at −12◦c to result in only liquid water at 0◦c?
melisa1 [442]

When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.

- Heat given out by water = Heat absorbed by ice

Calculating the heat released by hot water:

q = m CwaterΔTq = m (4.184\frac{J}{(g.^{0}C)} )(0^{0}C-50^{0}C)

Calculating heat absorbed by 16 g of ice: Ice at -12^{0}C is converted to ice at O^{0}C and then ice at O^{0} C to water at 0^{0}C

q = m CiceΔT + m (Heat of fusion)

q = 16 g(2.11\frac{J}{g.^{0}C})(0^{0}C - (-12^{0}C)) + 16 g (333.55\frac{J}{g})

q = 405.12 J +5336.8 J =5741.92 J

- Heat given out by water = Heat absorbed by ice

-(m(4.184\frac{J}{g.^{0}C})(0^{0}C-50^{0}C) = 5741.92 J

m = 27.4 g

Therefore, 27.4 g water at 50^{0}C must be added to 16 g of ice at -12^{0}C to convert to liquid water at 0^{0}C

4 0
3 years ago
If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what i
Ostrovityanka [42]

Consider the isomerization of butane with equilibrium constant is 2.5 .The system is originally at equilibrium with :

[butane]=1.0 M , [isobutane]=2.5 M

If 0.50 mol/L of butane is added to the original equilibrium mixture and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas?

Answer:

The equilibrium concentration of each gas:

[Butane] = 1.14 M

[isobutane] = 2.86 M

Explanation:

Butane  ⇄  Isobutane

At equilibrium

1.0 M               2.5 M

After addition of 0.50 M of butane:

(1.0 + 0.50) M               -

After equilibrium reestablishes:

(1.50-x)M            (2.5+x)

The equilibrium expression will wriiten as:

K_c=\frac{[Isobutane]}{[Butane]}

2.5=\frac{2.5+x}{(1.50-x)}

x = 0.36 M

The equilibrium concentration of each gas:

[Butane]= (1.50-x) = 1.50 M - 0.36M = 1.14 M

[isobutane]= (2.5+x) = 2.50 M + 0.36 M = 2.86 M

3 0
3 years ago
Which skin layer holds layers together
lions [1.4K]
The <span>epithelial hold the skin together.</span>
6 0
3 years ago
Antoine Henri Becquerel discovered radioactivity when he was studying
Katen [24]

Antoine Henri Becquerel discovered radioactivity when he was studying

X- rays.  

He had been studying phosphorescent uranium ores and hypothesized that they might absorb sunlight and reemit it as X-rays.

His hypothesis was wrong, but his experiments led to the discovery of <em>natural radioactivity</em>.

5 0
3 years ago
Read 2 more answers
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tatuchka [14]

Blood. It is discrete cells in saline solutuion. The cells are free to move thru the plasma, or you wouldn't have blood flow, or oxygenation, and you would die. Blood is defined as liquid, not jello.


The other three are things not normally associated--water will fall from the sky as rain, for example, but is held in suspension in fog. Same with the salad oil in mayo. O.J. can be a suspension; easily separated by a filter, Or a colloid--depends if the pulp, if Any, is held in suspension or not. Usually, pulp will settle to the bottom, making that sample of Orange juice a suspension. At different temperatures, it acts differently. But, so does Fog. A colloid is something that normally shouldn't be as some of its molecules are too dense to normally "float" in suspension. Colloid means "glue".



4 0
3 years ago
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