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Alina [70]
3 years ago
14

A scientist has a sample of uranium–238 (U–238) that is decaying to thorium–234 (Th–234). During the transmutation, a gamma ray

is emitted from the nucleus. The thorium–234 daughter particle does not decay quickly enough to be detected. What kind of storage container should he store the sample in to reduce radiation exposure? Explain your answer.
Chemistry
1 answer:
kykrilka [37]3 years ago
5 0

Answer:

  • <u>The container must be built of lead, and it should be kept in a concrete vault.</u>

Explanation:

The goal is to contain the <em>gamma rays</em> to<em> reduce</em> the <em>exposure </em>to their harmful <em>radiation</em>.

The gamma rays are the most energetic electromagnetic radiation: they have the smallest wavelength, the largest frequency, and the largest energy from all the electromagnetic radiations.

Due to that, only very dense substances like lead and concrete can stop the gamma rays. In the case of concrete, large blocks with thick walls are required.

Thus, in a lab the best container for a sample of uranium - 238 that is decaying, emitting gamma rays, must be built of lead, and enclosed in a conrete vault.

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iVinArrow [24]

Answer:

In non-polar covalent bonds, the electrons are equally shared between the two atoms. For atoms with differing electronegativity, the bond will be a polar covalent interaction, where the electrons will not be shared equally.

Explanation:

i did some reasherch so there^^

5 0
3 years ago
In each of the following sets of elements, which one will be least likely to gain or lose electrons?
klasskru [66]
1. The reactivity among the alkali metals increases as you go down the group due to the decrease in the effective nuclear charge from the increased shielding by the greater number of electrons. The greater the atomic number, the weaker the hold on the valence electron the nucleus has, and the more easily the element can lose the electron. Conversely, the lower the atomic number, the greater pull the nucleus has on the valence electron, and the less readily would the element be able to lose the electron (relatively speaking). Thus, in the first set comprising group I elements, sodium (Na) would be the least likely to lose its valence electron (and, for that matter, its core electrons).

2. The elements in this set are the group II alkaline earth metals, and they follow the same trend as the alkali metals. Of the elements here, beryllium (Be) would have the highest effective nuclear charge, and so it would be the least likely to lose its valence electrons. In fact, beryllium has a tendency not to lose (or gain) electrons, i.e., ionize, at all; it is unique among its congeners in that it tends to form covalent bonds.

3. While the alkali and alkaline earth metals would lose electrons to attain a noble gas configuration, the group VIIA halogens, as we have here, would need to gain a valence electron for an full octet. The trends in the group I and II elements are turned on their head for the halogens: The smaller the atomic number, the less shielding, and so the greater the pull by the nucleus to gain a valence electron. And as the atomic number increases (such as when you go down the group), the more shielding there is, the weaker the effective nuclear charge, and the lesser the tendency to gain a valence electron. Bromine (Br) has the largest atomic number among the halogens in this set, so an electron would feel the smallest pull from a bromine atom; bromine would thus be the least likely here to gain a valence electron.

4. The pattern for the elements in this set (the group VI chalcogens) generally follows that of the halogens. The greater the atomic number, the weaker the pull of the nucleus, and so the lesser the tendency to gain electrons. Tellurium (Te) has the highest atomic number among the elements in the set, and so it would be the least likely to gain electrons.
7 0
3 years ago
Can you help me with this?
Nikitich [7]

Answer:

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6 0
3 years ago
¿Qué hecho indujo a Heisenberg a establecer el principio de incertidumbre?
yaroslaw [1]

Answer:

Here's what I find  

Explanation:

Heisenberg observed that if we want to locate a moving electron, we must bounce photons off it.

However, this makes it recoil. By the time the photon returns to our eye, the electron will no longer be in the same place.

He concluded that there is a limit to the precision with which we can simultaneously measure the position and speed (momentum) of a particle.

The more precisely we know the electron's speed, the less precisely we know its position and vice versa.

The uncertainty in the product of the two values cannot be less than a fixed small number.

7 0
3 years ago
Is 3Al + 3FeO → 2Al2O3 + 3Fe a balenced or unbalenced equation?
Murrr4er [49]
3f+5=eo got it right
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