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yarga [219]
3 years ago
14

State whether the given set of angles form a triangle. Select all that apply.

Mathematics
2 answers:
elena55 [62]3 years ago
8 0

Answer:

Your answers are 1,4,5

Step-by-step explanation:

Triangles add up to 180 degrees, so all you have to do is add the degrees together.

86+53+41 = 180

47+84+56 = 187

70+22+68 = 160

54+97+29 = 180

33+90+57 = 180

Rainbow [258]3 years ago
6 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Angle sum property of a triangle.

To form a triangle, all angles must sum exactly to 180°.

So the correct options are :-

1.) 86°, 53°, 41°

4.) 54°, 97° , 29°

5.) 33° , 90° , 57°

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Andreyy89

Answer: 32

Step-by-step expanation:

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3 years ago
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The athlete’s salary, in thousands, for the first two years is $400 and $400(1.05). Explain how to find her salary for each of t
enyata [817]
To find the salary for the next three years, we are going to use the formula for the nth term of a geometric sequence: a_{n}=a_{1}r^{n-1}
where
a_{n} is the nth term of the sequence 
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To check if the values $400 and 400(1.05) for a geometric sequence, we are going to find their common ratio. To find the common ratio, we are going to use the formula r= \frac{a_{n} }{a_{n-1}}
where 
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a_{n-1} is the previous term in the sequence

We can infer from our values, that the current term of the sequence is 400(1.5), so a_{n-1}=400(1.5). That leaves 400 as the previous term, so a_{n-1}=400. Lets replace those values in our formula to find r:
r= \frac{a_{n} }{a_{n-1}}
r= \frac{400(1.05)}{400}
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Now that we have our common ratio, we can replace it in our formula for the nth term to find the athlete's salary for each of the next three years. Notice that the first term of our sequence is $400, so a_{1}=400
a_{n}=a_{1}r^{n-1}
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a_{4}=400(1.05)^{3}
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a_{5}=400(1.05)^{5-4}
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We can conclude that the athlete's salary for each of the next three years is: $441,$463.05,486.2025 respectively. Also, those vales for a geometric sequence because they share a common ratio, (1.05).
6 0
3 years ago
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