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Tems11 [23]
2 years ago
9

Consider a frictionless track as

Physics
1 answer:
Readme [11.4K]2 years ago
7 0

The maximum height to which block 1 rises after the collision   is 0.56m

<h3>What is mechanical energy?</h3>

The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.

M.E = KE +PE

A block of mass m1 = 5.00kg is released from A. It makes a head-on elastic collision at B with a block of mass m2= 10.0 kg that is initially at rest.

The conservation of energy principle states that total mechanical energy remains conserved in all situations where there is no external force acting on the system.

Kinetic energy before collision = Potential energy after collision

1/2 mu² =mgh

The velocity at the bottom, when the height h = 5m, is

u= √2gh

u = √2x 9.81 x5

u = 9.9 m/s

For elastic head on collision, final velocity of block 1 after collision is

v₁ = (m₁ -m₂)/ (m₁ +m₂) x u

Putting the values, we get

v₁ = -3.3 m/s

The final velocity of block 2 after collision is

v₂ = 2m₁ / (m₁ +m₂) x u

Putting the values, we get

v₂ =6.6 m/s

For block 1, after collision kinetic energy is converted to potential energy, then the maximum height rises

h' = v₁²/2g

h' = (-3.3)²/(2x9.81)

h' = 0.56 m

Thus, the height gained by the block after collision is 0.56 m.

Learn more about mechanical energy.

brainly.com/question/13552918

#SPJ1

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Explanation:

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3 years ago
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masha68 [24]

Answer:

5694000 min

Explanation:

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They watch 87600 min/year. Finally, let's calculate how many minutes they spend watching TV in 65 years.

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6 0
4 years ago
Match the layers of the atmosphere with the description that best matches it according to the graph titled Temperature Profile.
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The correct matches are as follows:

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Mesosphere
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Mesopause
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4 years ago
Read 2 more answers
A 2kg blob of putty moving at 4 m/s slams into a 6kg blob of putty at rest what is the speed of the to stick together blobs imme
andrew11 [14]
<h2>Answer</h2>

1m/s

<h2>Explanation</h2>

Given that:

<em>Mass of first blob = 2kg = m1</em>

<em>Velocity of blob = 4m/s = v1</em>

<em>Mass of second blob = 6kg = m2</em>

<em>Velocity of blob = 0m/s = v2</em>

<em />

To find:

<em>Final velocity = Vf</em>

<em />

<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>

<em />

<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>

(2*4) + (6*0) = Vf(2+6)

8 + 0 = Vf(8)

8 = Vf(8)

Vf = 1 m/s

So the speed of two blobs immediately after colliding = 1 m/s

3 0
3 years ago
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