Materials such as rubber, plastics, and glass do not carry electrical currents and<br> are known as

What is the acceleration of a car that goes from 40km/hr to 80km/hr in 2s?

tresset_1 [31]

Acceleration = v2 - v1 / t
a = 80 - 40 / 2
a = 40 / 2
a = 20 m/s²

In short, Your Answer would be 20 m/s²

Hope this helps!

5 0

3 years ago

The current in a hair dryer measures 22 amps. The resistance of the hair dryer is 14 ohms what is the voltage

lora16 [44]

(22 amps)(14 ohms)=308 V

4 0

3 years ago

What is uniforlmly acelerated motion and uniform motion

steposvetlana [31]

Uniformly Accelerated motion : When a body moves along a straight line and its velocity increases by equal amounts in equal interval of time then the motion is called uniformly accelerated motion. E.g.:- Motion of a freely falling body.

Uniform Motion : When a body covers equal distances in a straight line, equal intervals of time are called uniform motion. Example: a car moving at 20km/h in a straight line. When a body covers unequal distance in equal intervals of time in a straight line is called non-uniform Example : spinning wheel.

<h3>Difference About Uniformly Accelerated motion And Uniform Motion</h3>

In Uniform Velocity Motion a body will be moving with a constant /unchanging velocity moving in a particular direction and thus acceleration will be zero whereas in Uniform accelerated motion a body will move at constant acceleration and its velocity will keep changing with time at a constant/ steady rate.

<h2>IF YOU THINK MY ANSWER IS WRONG, CHANGE IT THANK YOU. </h2>

8 0

3 years ago

A satellite is launched to orbit the Earth at an altitude of 3.25 107 m for use in the Global Positioning System (GPS). Take the

Korolek [52]

Answer:Orbital period =21.22hrs

Explanation:

given that

mass of earth M = 5.97 x 10^24 kg

radius of a satellite's orbit, R= earth's radius + height of the satellite

6.38X 10^6 + 3.25 X10^7 m =3.89 X 10^7m

Speed of satellite, v= $\sqrt GM/R$

where G = 6.673 x 10-11 N m2/kg2

V= \sqrt (6.673x10^-11 x 5.97x10^ 24)/(3.89 X 10^ 7m)

V =10,241082.2

v= 3,200.2m/s

a) Orbital period

$\sqrt GM/R$ = $\frac{2\pi r}{T}$

V= $\frac{2\pi r}{T}$

T= 2 $\pi$ r/ V

= 2 X 3.142 X 3.89 X 10^7m/ 3,200.2m/s

=76,385.1 s

60 sec= 1min

60mins = 1hr

76,385.1s =hr

76,385.1/3600=21.22hrs

3 0

3 years ago

Earth turns on its axis about once every 24 hours. The Earth's equatorial radius is 6.38 x 106 m. If some catastrophe caused Ear

san4es73 [151]

To solve this problem it is necessary to apply the concepts related to the Period of a body and the relationship between angular velocity and linear velocity.

The angular velocity as a function of the period is described as

$\omega = \frac{2\pi}{T}$