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musickatia [10]
2 years ago
12

What is the 12th term of the sequence -2,-4,-6,...........-100?

Mathematics
2 answers:
ss7ja [257]2 years ago
8 0
-24 easy way is to time the number counting by and the term
Margaret [11]2 years ago
7 0

Answer:

-24

Step-by-step explanation:

You are just counting by two's.

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The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
Can you help stuck on this question for a while ​
stepladder [879]

Answer:

Option B

Step-by-step explanation:

Length of the rectangular sand box is given by the function,

F(x) = 3x³ + 6x - 2

Width of the sand box is represented by the function,

W(x) = 2x² - 4

Area function for the sand box will be,

Area of a rectangle = Length × Width

F(x) × W(x) = (3x³ + 6x - 2)(2x² - 4)

                 = 2x²(3x³ + 6x - 2) - 4(3x³ + 6x - 2)

                 = 6x⁵+ 12x³ - 4x²- 12x³- 24x + 8

                 = 6x⁵- 4x²- 24x + 8

Therefore, Area function will be represented by a polynomial degree of 5.

Option B will be the answer.

3 0
3 years ago
PLEASE HELP ME I WILL MARL BRAINLIEST use the line plot to answer the questions the line plot shows the wood strip lengths in in
Igoryamba

Answer:

we need an image or pic of the problem

3 0
3 years ago
Brainlyest
evablogger [386]
A. 36/a
B. 55-b
C.18+c
D.49d
E.e/62
7 0
3 years ago
One can of frosting covers about 280 square inches. Is one can of frosting enough to frost the cake?
kozerog [31]

Answer: Yes, because you only need 249 in^2 and it will cover 280 in^2

Step-by-step explanation:

SA=LW+2WH+2LH

SA=13(9)+2(9)(3)+2(13)(3)

SA=249 IN

4 0
3 years ago
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