<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>
As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.
Assumption : Let us assume the length as "l" and width as "b". So,
Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.
- <em>l</em> denotes length
- <em>b</em> denotes breadth


Now, finding the length. According to the question,

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>
Answer:
Option B
Step-by-step explanation:
Length of the rectangular sand box is given by the function,
F(x) = 3x³ + 6x - 2
Width of the sand box is represented by the function,
W(x) = 2x² - 4
Area function for the sand box will be,
Area of a rectangle = Length × Width
F(x) × W(x) = (3x³ + 6x - 2)(2x² - 4)
= 2x²(3x³ + 6x - 2) - 4(3x³ + 6x - 2)
= 6x⁵+ 12x³ - 4x²- 12x³- 24x + 8
= 6x⁵- 4x²- 24x + 8
Therefore, Area function will be represented by a polynomial degree of 5.
Option B will be the answer.
A. 36/a
B. 55-b
C.18+c
D.49d
E.e/62
Answer: Yes, because you only need 249 in^2 and it will cover 280 in^2
Step-by-step explanation:
SA=LW+2WH+2LH
SA=13(9)+2(9)(3)+2(13)(3)
SA=249 IN