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sergiy2304 [10]
2 years ago
15

What is the equilibrium constant of a reaction?

Chemistry
1 answer:
miskamm [114]2 years ago
5 0

Answer:

C. It is the ratio of the concentrations of products to the

concentrations of reactants.

Explanation:

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What’s the scientific notation for 654,000
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6.54 x 10^5

When trying to figure out a number in a scientific notation, use this notation! 

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Consider the aldol-dehydration reaction. Draw the two possible products of the reaction between benzaldehyde and methylethylketo
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Solution :

An $\text{aldol condensation}$ reaction is a type of \text{condensation reaction} in organic chemistry where the enol or an enolate ion reacts with the carbonyl compound and forms a $\beta$-hydroxyaldehyde or a $\beta$-hydroxyketone, and then followed by a dehydration to give conjugated enone.  

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Putting up 98 points! Will give medal
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A calorimeter contains 500 g of water at 25°C.....

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Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=
IgorC [24]

Answer: \Delta H^0=+0.3kJ/mol.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

S_{rhombic}+O_2(g)\rightarrow SO_2(g)    \Delta H^0_1=-296.06kJ   (1)

S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ  (2)

The final reaction is:  

S_{rhombic}\rightarrow S_{monoclinic}  \Delta H^0_3=?   (3)

By subtracting (1) and (2)

\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0
3 years ago
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