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sergiy2304 [10]
3 years ago
15

What is molecular formula

Chemistry
2 answers:
Vilka [71]3 years ago
4 0

Answer:

a formula giving the number of atoms of each of the elements present in one molecule of a specific compound.

Mazyrski [523]3 years ago
3 0

Answer:a formula giving the number of atoms of each of the elements present in one molecule of a specific compound.

Explanation:

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Which statement is true according to the kinetic theory?
Vlad [161]

Answer:

<em>Molecules of different gases with the same mass and temperature always have the same average kinetic energy - E.</em>

5 0
3 years ago
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How can grocery carts with different masses have the same acceleration?
Nezavi [6.7K]

Answer:

Yes

Explanation:

You add more force behind the cart with the higher mass. Assuming that its higher mass causes it to weigh more.

8 0
3 years ago
If an atom or ion has an atomic number of 3, 2 electrons, and the electronic configuration is 2, what is the mass number? ​
rjkz [21]
It’s mass number would be 5 as it’s the protons and the neutrons added together
7 0
3 years ago
How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
3 years ago
Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50
Reika [66]
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions. 
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
7 0
3 years ago
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