Sodium lends 1 electron.
Phosphorus borrows 3 electrons.
Potassium lends one electron.
Oxygen borrows 2 electrons.
Iodine borrows one electron.
Cesium lends 1 electron.
Bromine borrows 1 electron.
Sulfur borrows 2 electrons.
And magnesium lends 2 electrons.
As the given <span>moles OF ethanol = 0.040
now will find water moles that will b
moles of water = 1 - 0.040=0.96 (substract 1 from etahnol mole fraction)
now the
mass of water = 0.96 mol x 18.02 g/mol=17.3 g where 18 is atomic mass of water
mass of ethanol = 0.040 x 46 g/mol =1.84 g
now
mass of solution = 17.3 + 1.84=19.1 g that is mass of water +mass of etanol
Now
assume that the density of the solution = 1g/mL
so the
volume ofsolution = 19.1 mL = 0.0191 L
so finally the molarity will be
M = 0.040/ 0.0191=2.1
hope it helps</span>
Answer:
2.48 g
Explanation:
From the question given above, the following data were obtained:
Original amount (N₀) = 10 g
Time (t) = 1407.6 million years
Amount remaining (N) =?
Next, we shall determine the rate of decay (K) of uranium-235. This can be obtained as follow:
NOTE: Uranium-235 has a half life of 700 million years.
Decay constant (K) =?
Half life (t½) = 700 million years
K = 0.693/t½
K = 0.693/700
K = 9.9×10¯⁴ / year
Therefore, Uranium-235 decay at a rate of 9.9×10¯⁴ / year.
Finally, we shall determine the amount of Uranium-235 remaining after 1407.6 million years as follow:
Original amount (N₀) = 10 g
Time (t) = 1407.6 million years
Decay constant (K) = 9.9×10¯⁴ / year
Amount remaining (N) =?
Log (N₀/N) = kt /2.3
Log (10/N) = (9.9×10¯⁴ × 1407.6) /2.3
Log (10/N) = 0.60588
10/N = antilog (0.60588)
10/N = 4.04
Cross multiply
10 = 4.04 × N
Divide both side by 4.04
N = 10/4.04
N = 2.48 g
Therefore, 2.48 g of uranium-235 is remaining after 1407.6 million years.
Answer:
Explanation: Natural disasters are disasters that dont happen because of nature. A person does it.
What is the exoeruent. Searched it up on google and only came up with two search results. None related to chemistry
