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DanielleElmas [232]
3 years ago
13

Suppose a platinum atom in the oxidation state formed a complex with two chloride anions and two ammonia molecules. Write the ch

emical formula of this complex.
Chemistry
1 answer:
Korolek [52]3 years ago
7 0

Answer: Pt(Cl)2(NH3)2

Explanation:

In the formation of the complex, the oxidation number of platinum is plus two (+2) and two chloride ions cancel it out by their oxidation number of -1 each. Hence the complex has an overall charge of zero. It is thus neutral with no charge attached to its formula.

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When you mixed 20 grams of magnesium and an excess of nitric acid, 1.7 grams of hydrogen was actually produced. What is the perc
Kitty [74]
Based on the balanced chemical reaction presented above, every mole of magnesium (Mg) yields one mole of diatomic hydrogen (H2). When converted to masses, every 24.3 grams of magnesium yields 2 grams of hydrogen. 

From the given, there are 20 grams of magnesium available for the reaction. With this amount, the expected yield of hydrogen is 1.646 grams. To calculate the percent yield, divide the actual yield to the hypothetical yield.

*The case is impossible because the actual yield is greater than the theoretical yield.

If we assume that there had been a typographical error and that the actual yield is 0.7 grams instead of 1.7 grams, the percent yield becomes 42.5%. Thus, the answer is letter E. 
6 0
3 years ago
Read 2 more answers
Two samples of potassium iodide are decomposed into their constituent elements. The first sample produced 13.0g of potassium and
Leona [35]

Answer:

79.43kg

Explanation:

To adequately solve this problem, we should know the law of constant composition. This is a pointer to the fact that no matter the type of sample, the percentage compositions of potassium and iodine still remains the same. We can use these masses to get a formula and we would know the percentage compositions in whatever mass we are dealing with.

First of all, we add the masses in the first sample. 13 + 42.3 = 55.3

Hence, the percentage composition of the potassium is 13/55.3 * 100 = 23.51%

The percentage composition of the iodine is = 100 - 23.51 = 76.49%

Now, we need to get the formula of the compound. We can get this by dividing the percentage compositions with the atomic masses. The atomic mass of potassium and iodine is 39 and 127 respectively.

Potassium = 23.51/39 =0.603

Iodine = 76.49/127 = 0.602

We then divide by the smaller value to get the formula and this shoes our formula is KI

We can see they have a ratio of 1 to 1, meaning one atom of potassium to one atom of iodine. This further confirms the percentage compositions of 23.5 to 76.5

Now to get the mass of iodine yielded, let us say the mass is xkg

This means x/(x + 24.4) * 100 = 76.5

100x = 76.5( x + 24.4)

100x = 76.5x + 1866.6

100x - 76.5x = 1866.6

23.5x = 1866.6

x = 1866.6/23.5 = 79.43kg

4 0
2 years ago
How many ions in 6.41 moles of K2O? Please show work.
Oksana_A [137]
1. Convert the number of moles to number of particles (divide 6.41 by 6.022 x 10^23)

2. K2O dissociates into three ions (2 potassium ions and 1 oxide ion), so multiply the result from step 1 by 3 to get your answer
4 0
2 years ago
Whats kinetix energy​
MissTica

Explanation:

kinetic energy is the energy an object has while in motion, if I'm walking I have kinetic energy

8 0
3 years ago
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Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters He then puts
xxMikexx [17]

Answer:

gas is the correct answer.

Explanation:

8 0
2 years ago
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