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Oxana [17]
3 years ago
15

You dissolve 4.5 mol of potassium hydroxide to make a 2 L solution. What is the molarity of the solution?

Chemistry
1 answer:
pshichka [43]3 years ago
7 0
Data:
M (molarity) = ? (Mol/L)
m (mass) = ? (in grams)
V (volume) = 2 L 
MM (Molar Mass) of Potassium Hydroxide (KOH)
K = 1*39 = 39 amu
O = 1*16 = 16 amu
H = 1*1 = 1 amu
------------------------------------
MM  of KOH = 39+16+1 = 56 g/mol

***<span>Let's find the mass
</span>Data:
n (number of mols) = 4.5 mols
m (mass) = ? (in grams)
v (volume) = 2 L

Formula:

n =  \frac{m}{V}
4.5 = \frac{m}{2}
m = 4.5*2
\boxed{m = 9.0\:g}

***<span>Let's find the molarity:
</span>
Formula:

M = \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
M = \frac{9.0}{56*2}
M = \frac{9.0}{112}
M = 0.0803...\:\to\:\boxed{\boxed{M \approx 0.08\:Mol/L}}\end{array}}\qquad\quad\checkmark



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