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1 year ago

What is the difference between -5 and 3?

Mathematics

2 answers:

Cerrena [4.2K]1 year ago

7 0

8 because 3- -5=8 when u subtract a negative from a negative it becomes positive

kozerog [31]1 year ago

4 0

Answer:

Step-by-step explanation:

3 - -5 = 8

filling space here dont mind this

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Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

2 years ago

-2x^4 +50x^2+0x-3/x-5

Gemiola [76]

1) "x2" was replaced by "x^2". 1 more similar replacement(s).
Raising zero to a power is not allowed

3 0

3 years ago

10. When a rubber ball is dropped from a height, h cm on to a flat concrete floor, it rebounds to 3 5 h cm a height of Given a r

Xelga [282]

Step-by-step explanation:

Let the height above which the ball is released be H

This problem can be tackled using geometric progression.

The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is

To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H

a=2H..........r=3/4

However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H

Therefore the total distance travel up to the Nth bounce is

For N=3 one obtains

D=3.625H

7 0

2 years ago

Please ASAP please

Mars2501 [29]

Answer:

A)3.125hr

B)53.325mi

Step-by-step explanation:

speed=distance/time

an hour and 15min=1.25hr

32/1.25=25.6mi/hr

80/25.6=3.125hr

2hr and 5min=2+5/60=2.083hr

2.083x25.6=53.325mile

7 0

2 years ago

Express the missing divisor using the power of 10

allochka39001 [22]

Theres not enough information to answer this for you,

8 0

3 years ago

Read 2 more answers