This is the visible light spectrum is the only portion that the human eye can detect or "see".
<span>Kp is the equilibrium pressure constant calculated from the partial pressures of a reaction equation.
Kp =[pCF4]*[p CO2] / [p COF2]^2 = 2.2 x 10^6
When the mole fraction gets doubled we have
Kp = [pCO2]^2*[pCF4]^2 / [pCOF2]^4
Kp = [[pCF4]*[p CO2] / [p COF2]^2] * 2
Kp = (2.2 * 10^6) * 2
Kp = 4.8 * 10^12</span>
Answer:
I believe it would be 2
Explanation:
if there are 2 nitrogen molecules then there would have to be 2 hydrogen molecules but this could be completely wrong
if this happens to be right, ur welcome :3 here's a Jay Jay pic for u cuz why not
The questions you can answer are
1) what is the mass of one mole of raindrops?, and
2) How many moles of raindrops are in the pacific ocean
Solutions:
1) what is the mass of one mole of raindrops?
mass = number of rain drops * mass of on rain drop
The number of rain drops in one mole of rain drops is 6.02 * 10^23
So, the mass of one mole of rain drops is
6.02 * 10 ^ 23 rain drops * 50. mg * (1 kg / 1,000,000 mg) = 3.01 * 10^ 19 kg
The correct number of significant digits is 2, because 50. mg has two signficant digits, so the answer must be shown as 3.0 * 10^ 19 kg.
2) How many moles of raindrops are in the pacific ocean
Use the proportion 1 mol / 3.0 * 10^19 kg = x mol / 7.08 * 10^20 kg
And you solve for x:
x = (7.08 * 10^20 kg) * 1 mol / (3.0 * 10^19 kg) = 2.36 * 10 = 23.6 moles
Which rounded to two significant digits is 24 moles of rain drops.