Answer:
The sun would appear to move more slowly across Mercury's sky.
Explanation:
This is because, the time it takes to do one spin or revolution on Mercury is 176 days (which is its period), whereas, the time it takes to do one spin or revolution on the Earth is 1 day.
Since the angular speed ω = 2π/T where T = period
So on Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = 15,206,400 s
So, ω' = 2π/T'
= 2π/15,206,400 s
= 4.132 × 10⁻⁷ rad/s
So on Earth, T" = 1 day = 1 day × 24 hr/day × 60 min/hr × 60 s/min = 86,400 s
So, ω" = 2π/T"
= 2π/86,400 s
= 7.272 × 10⁻⁵ rad/s
Since ω' = 4.132 × 10⁻⁷ rad/s << ω" = 7.272 × 10⁻⁵ rad/s, <u>the sun would appear to move more slowly across Mercury's sky.</u>
Amu valie on the top and abundsnce percent in decimals on the bottom for each isotope
Answer:
Explanation:
so u can work out the amount of moles in FeO3 by doing mr of fe3o3 is 55.8*3+16*3=215.4
moles= mass/mr so you do 15.5g/215.4=0.0719 moles
then using 1 to 1 ratio so O2 moles is 0.0719
then use the equation mass=mole*mr
so 0.0719*16=1.15g
hope this make sense :)
