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snow_lady [41]
3 years ago
7

PLEASE HELP!!!

Chemistry
1 answer:
Brums [2.3K]3 years ago
4 0

Answer: I believe the answer is A

Explanation:

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Give the common name for the structure. ethyl isopropyl ketone tert-butyl ethyl ketone sec-butyl ethyl ketone ethyl isobutyl ket
salantis [7]
The structure for this question is attached. I think the correct answer would be the fourth option. The common name of the structure would be ethyl isobutyl ketone. Other name would be 2-methyl-3-pentanone. It has a chemical formula of C7H14O or (CH3)2CHCH2C(O)CH2CH3. It is classified as an aliphatic ketone and is used as a solvent and a reagent in laboratory experiments. It is a VOC or volatile organic compound. This compound can also be found at times in normal human biofluids and in feces for about 25% of the population. At normal conditions, it exists as a solid compound. 

6 0
3 years ago
What form of heat transfer makes warm air rise?
zlopas [31]
Convection which allows heat to be transferred between the air molecule via convection currents .
3 0
3 years ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
A container holds 6. 4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.
ipn [44]

In a mixture of gases, the total pressure is equivalent to the aggregate of all the partial pressures of the single element of the gas.

It can be written as \rm P _{total} = P₁ + P₂ +  P₃ and so on.

The partial pressure will be:

Option A. 0. 31 atm

Pressure can be estimated by:

<u>PV = nRT</u>

\rm P_{total} = \dfrac{n _{total }RT}{ V}

\rm P_{total} = \dfrac{n _{H_{2}} + n _{\rm other \;gases}}{ V}

Where,

\rm nH_{2} = 25\% \times n_{Total}

And,

\begin{aligned}\rm P_{H_{2}} &= 25\% \times \rm P_{Total}\\\\& = 25\% \times 1.24 \;\rm atm\\\\& = 1.24 \rm \;atm \times 25 \end{aligned}

Solving finally we get,

\rm  P_{H_{2}} = 0.31 \;\rm atm

Therefore, 0.31 atm is the partial pressure of the hydrogen gas.

To learn more about partial pressure follow the link:

brainly.com/question/1471705

3 0
3 years ago
the freezing point depression constants of the solvents cyclohexane and naphthalene are 20.1°C/m and 6.94°C/m respectively. Whic
Evgesh-ka [11]

Explanation:

It'd be better to use cyclohexane.  The possible explanation is that the freezing temperature will change by 20.1 degrees for each mole of substance added to 1 kg of cyclohexane, although the same amount added to naphthalene will change its freezing point just by 6.94 degrees.

It is so much easier to identify a larger change more adequately than a smaller one.  You would actually not have a 1 molal solution in operation, so the variations in freezing points would be even smaller than the ones already described.

7 0
3 years ago
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