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2 years ago

Would it ever be possible for the temperature in Celsius to have a greater value than the temperature in Fahrenheit?

Chemistry

1 answer:

Dafna11 [192]2 years ago

8 0

Because Celsius is always (Fahrenheit -32) /1.8 , so its always going to be a smaller number than F. Does that help?

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Please help!!! DUE IN 10 minutes

NARA [144]

Answer:

232.04

Explanation:

90 - atomic number

Th - element symbol

232.04 - atomic mass

4 0

2 years ago

Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?

Andreas93 [3]

Answer:

no lo sé chico ve a morir en un agujero

Explanation:

8 0

2 years ago

Pls it’s urgent

Rainbow [258]

Answer:

0.02 moles.

Explanation:

volume of H₂ gas at R.T.P = 480 cm³

Where

R.T.P = room temperature and pressure

molar volume of gas at = 24000 cm³

no. of moles of hydrogen = ?

Solution:

formula Used

no. of moles = volume of gas / molar volume

put values in above equation

no. of moles = 480 cm³ / 24000 cm³/mol

no. of moles = 0.02 mol

So,

no. of moles of hydrogen in 480 cm³ is 0.02 moles.

4 0

2 years ago

How does the law of conservation of mass apply to this reaction:Mg + 2HCl → H2 + MgCl2?

krok68 [10]

The law of conservation of mass applies to every reaction. In this case, you start with 1 Mg, 2 H, and 2CL and end up with the same five only their bonds have been rearranged, or in other words, they are joined up differently.

5 0

2 years ago

if 28.5 g of calcium hydroxide is dissolved in enough water to make 185g of solution what is the percent by mass of calcium hydr

DENIUS [597]

The percent by mass of calcium hydroxide in the solution : 15.41%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5

Mass of solution = 185 g

$\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%\\\\\%mass=\dfrac{28.5~g}{185~g}\times 100\%\\\\\%mass=15.41\%$

6 0

2 years ago