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Usimov [2.4K]
2 years ago
13

Can anyone please answer this cq..

Physics
1 answer:
ZanzabumX [31]2 years ago
6 0
Hqisgshsjsvg udyfudueuduutuufududuydd
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Take a car collision as an example, the more you speed up as means of acceleration, the more force will be on impact.
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Question 10 of 34
labwork [276]

Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.

<h3>What is displacement?</h3>

Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.

Displacement is a vector quantity .its unit is m.

The average velocity on this walk will be;

\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4  \ block /min

Hence option B is correct.

To learn more about displacement refer to the link; brainly.com/question/10919017

#SPJ1

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2 years ago
A person should power walk for minutes a day in order to benefit from this activity
larisa86 [58]
A person should power walk 30-45 min a day
3 0
3 years ago
Read 2 more answers
Please answer and show work:
Vinvika [58]
The answer is c
Distance/speed=time
Therefore 4000/500=8
6 0
3 years ago
4. Consider a 1 kg block is on a 45° slope of ice. It is connected to a 0.4 kg block by a cable
icang [17]

If an icy surface means no friction, then Newton's second law tells us the net forces on either block are

• <em>m</em> = 1 kg:

∑ <em>F</em> (parallel) = <em>mg</em> sin(45°) - <em>T</em> = <em>ma</em> … … … [1]

∑ <em>F</em> (perpendicular) = <em>n</em> - <em>mg</em> cos(45°) = 0

Notice that we're taking down-the-slope to be positive direction parallel to the surface.

• <em>m</em> = 0.4 kg:

∑ <em>F</em> (vertical) = <em>T</em> - <em>mg</em> = <em>ma</em> … … … [2]

<em />

Adding equations [1] and [2] eliminates <em>T</em>, so that

((1 kg) <em>g</em> sin(45°) - <em>T </em>) + (<em>T</em> - (0.4 kg) <em>g</em>) = (1 kg + 0.4 kg) <em>a</em>

(1 kg) <em>g</em> sin(45°) - (0.4 kg) <em>g</em> = (1.4 kg) <em>a</em>

==>   <em>a</em> ≈ 2.15 m/s²

The fact that <em>a</em> is positive indicates that the 1-kg block is moving down the slope. We already found the acceleration is <em>a</em> ≈ 2.15 m/s², which means the net force on the block would be ∑ <em>F</em> = <em>ma</em> ≈ (1 kg) (2.15 m/s²) = 2.15 N directed down the slope.

8 0
3 years ago
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