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Usimov [2.4K]
2 years ago
13

Can anyone please answer this cq..

Physics
1 answer:
ZanzabumX [31]2 years ago
6 0
Hqisgshsjsvg udyfudueuduutuufududuydd
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A grocery shopper tosses a(n) 9.1 kg bag of
spin [16.1K]

Answer:

2.1 m/s

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

(9.1 kg) (6.6 m/s) = (9.1 kg + 19.3 kg) v

v = 2.1 m/s

3 0
3 years ago
What is surface tension ​
harina [27]

Answer:

Surface tension is,  the surface where the water meets the air, water molecules cling even more tightly to each other.

5 0
3 years ago
If you cut a permanent magnet into four pieces,
lora16 [44]

you would have C) two north poles and two south poles

8 0
3 years ago
Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let a = 200 N and b = 400 N. Round y
omeli [17]

Answer: R = 346.4N and angle 30° to the horizontal negative axis

Explanation:

To find the resultant force, we need to sum up the forces on the vertical and horizontal axis.

For the horizontal axis;

Rx = -b + acos60

Rx = -400N +200cos60

Rx = -400N +100N

Rx = -300N

For the vertical axis;

Ry = asin60 = 200sin60

Ry = 173.2N

The resultant force R can be given as;

R = √(Rx^2 +Ry^2)

R = √((-300)^2 + 173.2^2)

R = 346.4N

Angle z can be written as

Tanz = Ry/Rx

z = taninverse (Ry/Rx)

z = taninverse (173.2/300)

z = 30°

6 0
3 years ago
An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto
kupik [55]

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

4 0
4 years ago
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