Question

A and b are positive integers and 7a+ 5b= 49. Find the values of a and b.

Answer 1

Answer:

B = 49/5 - 7a/5

A = = -5b/7 + 7

Step-by-step explanation:

Given that,

7a+ 5b= 49

Solution:

Solving for a:

Add -5b to both sides:

• $7a+5b - 5b=49 - 5b$
• $7a = - 5b + 49$

Divide both sides by 7:

• $\cfrac{7a}{7} = \cfrac{ - 5b + 49}{7}$
• $a = \cfrac{ - 5b}{7} + 7$

Hence,a = -5b/7 + 7.

Solving for b:

Add -7a to both sides:

• $7a+5b+( - 7a)=49+(−7a)$
• $7a + 5b - 7a = 49 - 7a$
• $5b = 49 - 7a$

Divide both sides by 5:

• $\cfrac{5b}{5} = \cfrac{49 - 7a}{5}$
• $b = \cfrac{49}{5} - \cfrac{7a}{5}$

Hence,b = 49/5 - 7a/5.