Answer:
As it gets hydrolyzed easily.
Explanation:
The isocyanic acid may get polymerizes easily into cyanuric acid and a polymer cyamelide
Also, even at 0 °C temperature it may react with mositure and gets hydrolyzed into ammonia an carbon dioxide. Thus we generally prepare it in situ. Even after synthesis it is stroed at dry ice or liquid nitrogen at very low temperature.
The lewis structure is shown in the figure.
Answer:
The molar mass of the unknown gas is 100.4 g/mol
Explanation:
Step 1: Data given
Molar mass of argon = 39.95 g/mol
After filling with argon the flask gained 3.221 grams
After filling with an unknown gas, the flask gained 8.107 grams
Step 2: Calculate the molar mass of the unknown gas
The gas with the higher molar mass will have the higher density.
Ar - 3.224 g; molar mass = 39.95 g/mol
X = 8.102 g; molar mass = ??
Molar mass of the unknown gas = 8.102g X *(39.95 g/mol / 3.224 g) = 100.4 g/mol
The molar mass of the unknown gas is 100.4 g/mol
Answer: Chemical X H3 and f1
Explanation:
KOH is a strong base and HBr is a strong acid and completely dissociates.
The balanced equation for the reaction is;
KOH + HBr ---> KBr + H₂O
Stoichiometry of acid to base is 1:1
The number of KOH moles reacted - 0.50 M / 1000 mL/L x 48.0 mL = 0.024 mol
number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL = 0.024 mol
the number of H⁺ ions are equal to number of OH⁻ ions.
Then the solution is neutral.
pH of neutral solutions at 25 °C is 7.
Therefore pH is 7
